A semipermeable membrane is placed between the following solutions. Which solution will decrease in volume? Solution A: 1.31% (m
/v) starch Solution B: 7.48% (m/v) starch 2.A semipermeable membrane is placed between the following solutions. Which solution will increase in volume? Solution C: 6.75% NaCl Solution D: 11.7% NaCl
1. The volume of solution A (1.31%) will decrease.
2. The volume of solution D (11.7%) will increase.
Explanation:
1. If two solutions are separated by a semipermeable membrane, the water molecules will move through the membrane starting from the solution that has the low concentration of the solute towards the solution that has a high concentration of the solute. Therefore, if solution A has 1.31% starch and solution B has 7.48% starch, it can be seen that solution B has a higher concentration. This is why the water molecules will move from Solution A to Solution B.
2. Like exercise 1, solution C has a concentration of 6.75% NaCl and solution D has a concentration of 11.7% NaCl. Therefore, with solution D having a higher concentration, the water molecules will move from solution to solution D.
When acetylene reacts with silver nitrate, its acidic hydrogen reacts with silver nitrate to form a white precipitate. So here acetylene shows its acidic nature.
