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tester [92]
2 years ago
12

A semipermeable membrane is placed between the following solutions. Which solution will decrease in volume? Solution A: 1.31% (m

/v) starch Solution B: 7.48% (m/v) starch 2.A semipermeable membrane is placed between the following solutions. Which solution will increase in volume? Solution C: 6.75% NaCl Solution D: 11.7% NaCl
Chemistry
2 answers:
Lady_Fox [76]2 years ago
7 0

Answer:

1. The volume of solution A (1.31%) will decrease.

2. The volume of solution D (11.7%) will increase.

Explanation:

1. If two solutions are separated by a semipermeable membrane, the water molecules will move through the membrane starting from the solution that has the low concentration of the solute towards the solution that has a high concentration of the solute. Therefore, if solution A has 1.31% starch and solution B has 7.48% starch, it can be seen that solution B has a higher concentration. This is why the water molecules will move from Solution A to Solution B.

2. Like exercise 1, solution C has a concentration of 6.75% NaCl and solution D has a concentration of 11.7% NaCl. Therefore, with solution D having a higher concentration, the water molecules will move from solution to solution D.

Zigmanuir [339]2 years ago
5 0

Answer:

Are you in flvs, if so im prettyb sure if yo look on page 3 of lesson 1.04 it tells you the answer.

Explanation:

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Answer:

The precipitate was chromium hydroxide, which then reacted with more hydroxide to produce a soluble complex, Cr(OH)4

Explanation:

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The precipitate that is formed is chromium hydroxide, Cr(OH)_{3}

When more NaOH is added, the precipitate reacts with it which then results in the formation of a soluble complex ion:

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Answer:

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