The mass percent of potassium chloride is 1.386%
<u><em>calculation</em></u>
mass percent = actual mass/ Theoretical mass x 100
Actual mass = 9.35 g
Theoretical mass is calculated as below
Step 1 : write the equation for reaction
KCl + H₂O → KOH + HCl
Step 2: find the moles of H₂O
moles = mass÷ molar mass
The molar mass of H₂O = (2 x1 ) +(16) = 18 g/mol
moles is therefore = 162.98 g÷ 18 g/mol =9.054 moles
Step 3: use the mole ratio to determine the moles of KCl
KCl: H₂O is 1:1 therefore the moles of KCl is also = 9.054 moles
Step 4: find the theoretical mass of KCl
mass = moles x molar mass
from periodic table the molar mass of KCl = 39 +35.5 =74.5 g/mol
mass = 9.054 moles x 74.5 g/mol =674.5 g
Theoretical mass is therefore = 9.35 g/ 674.5 g x 100 = 1.386%
Answer:
Because the model makes the concepts easier to understand
Explanation:
Models are created to give a visual of every aspect of an experiment. This allows for a better understanding across the board for everyone.
Answer:
Explanation:
<u>The alkaline solution: </u>
40 ml of 0.1 M KOH
<u>The acid solution: </u>
30 ml of 0.1 M HCl
The neutralization reaction:
For 1 mol of HCl, 1 mol of KOH is consumed. If 0.003 mol of HCl are added, 0.003 mol of KOH reacted.
After titration:
Concentration (don't forget to add the volumes)
Calcualtion of the pOH:
![pOH=-log([OH^-])=-log(0.0143)=1.84](https://tex.z-dn.net/?f=pOH%3D-log%28%5BOH%5E-%5D%29%3D-log%280.0143%29%3D1.84)
For the pH:
Answer:
B.
Explanation:
One mole is the amount of substance that contain the Avogadro number which is equal to 6.022×10^23 atom, molecules or ions.
Rate of the reaction is represented as
Rate=k[A][B]
Rate represents change in product concentration with time that has a unit Ms- Whereas concentration of each reactant can be represented as M . so the expression will become:
Ms-1=k[M][M]
k=M-1 s-1.
