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AlexFokin [52]
3 years ago
8

For a cell whose potential is –0.46 v with 3 moles of electrons exchanged, what is ΔG ? ΔG = –nFE°cell

Chemistry
2 answers:
jeka57 [31]3 years ago
8 0

Answer:

133kj

Explanation:

Nimfa-mama [501]3 years ago
4 0
<span>ΔG is 133kJ
</span>
ΔG = –nFE°cell
ΔG =  free energy of the reaction = ?
n = no of moles of electrons exchanged in the reaction = 3
F = Faraday's constant (9.648456 x 10^{4}C/mol)E_{0} =  cell potential = <span>–0.46 v
</span>
⇒ ΔG = –nFE°cell
⇒ ΔG = - (3 mol)(9.648456 x 10^{4} C/mol) (-0.46 J/C) ⇒ ΔG = +133148 J ≈ 133 kJ
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