Question

Determine which set of side measurements could be used to form a right triangle.

Answer 1

The sets $(\sqrt{7}, 4, \sqrt{23})$ and$(\sqrt{29}, \sqrt{39}, 68)$ could be used to form a right triangle.

What is right triangle?

A right triangle, also known as a right-angled triangle, an orthogonal triangle, or historically a rectangled triangle, is a triangle with one right angle, meaning that its two sides are perpendicular. Trigonometry's foundation is the relationship between the right triangle's sides and other angles.

Since for the right triangle is a, b, c are three sides of a triangle, where c is the diagonal, then

$a^2 + b^2 = c^2$

Consider, the set  (3, 5, 8)

Here,  3^2 + 5^2 ≠ 8^2.

Consider, the set (8, 9, 11)

Here, 8^2 + 9^2 ≠ 11^2

Consider, the set $(\sqrt{7}, 4, \sqrt{23})$

Here, $(\sqrt{7})^2 + 4^2 = (\sqrt{23})^2$

Consider, the set $(\sqrt{29}, \sqrt{39}, 68)$

Here, $(\sqrt{29})^2 + (\sqrt{39})^2 = 68$

Hence, $(\sqrt{7}, 4, \sqrt{23})$, $(\sqrt{29}, \sqrt{39}, 68)$ could be used to form a right triangle.

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Answer 2

Answer:  square root of 7 comma 4 comma square root of 23

Step-by-step explanation: I took the test and I got it right