How can you express (32 + 56) as a multiple of a sum of whole numbers with no common factor?

1 answer:

5 0

To express (32+56) as a multiple sum of whole number we proceed as follows;
32=2*2*2*2*2=2^5
56=2*2*2*5=(2^3)*5
Thus;
(32+56)
=2^5+2^3*5
=2^3(2^2+5)
The answer is:
2^3(2^2+5)

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