The case is acidic since calculated pH is below 7 that is 2.3
The hydroxide and hydrogen ion levels in a solution are the sources for calculating pOH and pH levels, respectively, and are the basis of whether a solution is acidic or basic
[H₃O+]=5.3×10⁻³M
To determine the hydroxide ion concentration, we use:
[OH−][H3O+]=1×10⁻¹⁴
We isolate the hydroxide ion concentration:
[OH−]=1×10−145.3×10⁻³M
Solving this, we obtain:
[OH−]=1.9×10−¹²M
We can determine whether the solution is acidic or basic by calculating the pH level:
pH=−log[H3O+]
We substitute in the hydronium ion concentration given:
pH=−Log(5.3×10−3)pH=2.3
Since the pH is below 7, the solution is acidic
Learn more about hydroxide ion here-
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Answer:
225 mL of water must be added.
Explanation:
First we <u>calculate how many HCl moles are there in 516 mL of a 0.191 M solution</u>:
- 516 mL * 0.191 M = 98.556 mmol HCl
Now we use that number of moles (that remain constant during the <em>dilution process</em>) to <u>calculate the final volume of the 0.133 M solution</u>:
- 98.556 mmol / 0.133 M = 741 mL
We can <u>calculate the volume of water required</u> from the volume difference:
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Answer:
Element atom molar mass Total % composition
Na 1 23 40 57.5 %
O 1 16 40 40%
H 1 1 40 2.5 %
The given compound is NaOH.
Na : number of atom= 1
Molar mass= 23 g/mol
Total mass of NaOH = 40 g/mol
% composition by mass = 
O : number of atom= 1
Molar mass= 16 g/mol
Total mass of NaOH = 40 g/mol
% composition by mass = 
H : number of atom= 1
Molar mass= 1 g/mol
Total mass of NaOH = 40 g/mol
% composition by mass = 
easy there are three levels so you look at the periodic table and go to the third row now the last level on this atom is 1 electron so your answer is <u>Na</u>
