Question

Find a solution of the quadratic equation.6x squared + 7x + 2 =0

Answer 1

Given the equation:

$6x^2+7x+2=0$

We will use the following rule to find the solution to the equation:

$x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

From the given equation: a = 6, b = 7, c = 2

So,

$\begin{gathered} x=\frac{-7\pm\sqrt[]{7^2-4\cdot6\cdot2}}{2\cdot6}=\frac{-7\pm\sqrt[]{1}}{12}=\frac{-7\pm1}{12} \\ x=\frac{-7-1}{12}=-\frac{8}{12}=-\frac{2}{3} \\ or,x=\frac{-7+1}{12}=-\frac{6}{12}=-\frac{1}{2} \end{gathered}$

So, the answer will be option B) x = -1/2, -2/3