Let width and length be x and y respectively.
Perimeter (32in) =2x+2y=> 16=x+y => y=16-x
Area, A = xy = x(16-x) = 16x-x^2
The function to maximize is area: A=16 x-x^2
For maximum area, the first derivative of A =0 => A'=16-2x =0
Solving for x: 16-2x=0 =>2x=16 => x=8 in
And therefore, y=16-8 = 8 in
Answer:
C
Step-by-step explanation:
substitute -1 into all of the formulas, if both sides are equal, then it is correct, for C:
2(x-2)+6 = 0, sub -1
2(-1-2)+6=0, simplify and work out
2(-3)+6=0
-6+6=0
0=0
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