Using the t-distribution, as we have the standard deviation for the sample, it is found that the 95% confidence interval estimate for the mean number of calories for servings of breakfast cereals is (195.3, 215.7).
<h3>What is a t-distribution confidence interval?</h3>
The confidence interval is:
In which:
- is the sample mean.
- t is the critical value.
- n is the sample size.
- s is the standard deviation for the sample.
From the sample and the significance level of 0.05, we have that the parameters are given by:
Hence:
The 95% confidence interval estimate for the mean number of calories for servings of breakfast cereals is (195.3, 215.7).
More can be learned about the t-distribution at brainly.com/question/16162795
I think the answer is 2.07, I’m not positive so I’m really sorry if I’m wrong
I can’t see it it too blurry
Answer:
All Calendula College students enrolled in the spring.
Step-by-step explanation:
A researcher at Calendula College wishes to estimate the number of units earned by students during the spring semester at Calendula.
To do so, he randomly selects 100 student transcripts from among all Calendula College students enrolled in the spring and records the number of units each student earned in the spring term.