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3 years ago

Somebody please help algebra nation doesn’t help

Mathematics

1 answer:

Elena L [17]3 years ago

3 0

What the question is really asking for is the x-intercept (the point at which the graph crosses the x-axis), which, according to the graph, is 6.

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The profit from a business is

GuDViN [60]

First of all we will understand the question!!

The question is saying that you are given a function and you have to find the value of x which will give the maximum profit... Lets solve it by finding the extrema using the vertex

 $\rm \: p(x) = - 5 {x}^{2} + 30x + 8$ 

Identify the coefficients a and b of the quadratic function

 $\rm \: p(x) = { - 5x}^{2} + 30x + 8 \\ \rm \: a = - 5 \: and \: b \: = 30$ 

Since a<0, the function has the maximum value at x, calculated by substituting a and b into x=-b/2a

$\rm \: x = \frac{30}{ 2 \times (- 5)}$

Solve the equation for x

$\rm \: x = 3$

The maximum of the quadratic function is at x=3

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1 year ago

• The ratio of cookies to eggs was 9 to

UkoKoshka [18]

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2 years ago

Daniel clearly chose a unit of measure (miles) that was too big for the construction work he was doing. Tape measures do not hav

Leokris [45]

Answer:

personally i would use a.

Step-by-step explanation:

this is my answer and opinion btw

5 0

2 years ago

Read the proof. Given: AB ∥ DE Prove: △ACB ~ △DCE Triangle A B C is shown. Line D E is drawn inside of the triangle and is paral

NikAS [45]

Answer:

(A) AA Similarity Theorem

Step-by-step explanation:

Given: AB ∥ DE

To Prove: $\triangle ACB \sim \triangle DCE$

Given Triangle ABC with Line DE drawn inside of the triangle and parallel to side AB. The line DE forms a new triangle DCE.

Because AB∥DE and segment CB crosses both lines, we can consider segment CB a transversal of the parallel lines.

Angles CED and CBA are corresponding angles of transversal CB and are therefore congruent, so ∠CED ≅ ∠CBA.

We can state ∠C ≅ ∠C using the reflexive property.

Therefore, $\triangle ACB \sim \triangle DCE$ by the AA similarity theorem.

Remark: In the diagram, we can see that the two triangles share Angle C and have two equal angles at E and B. Therefore, they are similar by the Angle-Angle Similarity Theorem.

7 0

3 years ago

(-25)raised to the -4 power times (5 raised to the -3 power) raised to the -2 powerI'll upload a picture

nordsb [41]

Hello there. To solve this question, we need to remember some properties on powers.

(-25)^(-4) * (5^(-3))^(-2)

To start, remember a^(-n) = 1/a^n, for a not equal to 0. Also, (ab)^n = a^n * b^n and (a^b)^c = a^(b*c)

Such that we have:

(-1)^(-4) * 25^(-4) * 5^((-3)*(-2))

1/(-1)^4 * (5^2)^(-4) * 5^6

Since (-1)^4 is equal to 1, we get:

5^(2*(-4)) * 5^6

5^(-8) * 5^6

Knowing that a^b * a^c = a^(b + c), we get:

5^(-8+6)

5^(-2)

Applying the first rule, we get:

1/5^2

1/25.

6 0

1 year ago

Read 2 more answers