What are the zeros of the polynomial function f(x) = x3 − 2x2 − 24x?

Mathematics

1 answer:

Morgarella [4.7K]3 years ago

4 0

Answer:

x = 0, x = -4, and x = 6

Step-by-step explanation:

To find the zeros of this polynomial, we can begin by factoring out a common factor of each term. 'x' is a common factor. We can distribute this variable out, giving us:

f(x) = x(x²- 2x- 24)

Now, factor the polynomial inside of the parenthesis into its simplest form. Factors of -24 that add up to -2 are -4 and 6.

f(x) = x( x + 4) (x - 6)

From this, we can derive the zeros x = 0, x = -4 and x = 6.

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babunello [35]

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6 0

3 years ago

How to graph 2y-10x=20

aksik [14]

First, put it into slope/intercept form so you can see what you've got.

"Slope/intercept form" is  y = everything else .

So that means you have to take the equation you have and "solve it for 'y' ".

2y - 10x = 20

Add 10x to each side: 2y = 10x + 20

Divide each side by 2 :  y = 5x + 10

There it is.
Now that you have it in that form, you can just look at it and see that the
slope of the line on the graph is 5, and the line crosses the y-axis at 10.

And that's exactly the information you need to graph it. On your graph,
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3 years ago

What equation represents the model shown below?

g100num [7]

Given:

The algebra tiles of an equation.

To find:

The equation represented by the given model.

Solution:

On the left side of the model we have 4 tiles of (-x) and 3 tiles of (-1). So,

$LHS=(-x)+(-x)+(-x)+(-x)+(-1)+(-1)+(-1)$