The midpoint of the segment with the following endpoints, (4, 2) and
(7, 6) is (5.5, 4).
How to determine the midpoint of a given segment?
The center point of a straight line can be located using the midpoint formula. We can use this midpoint formula to determine the coordinates of the supplied line's midpoint in order to discover its location on a graph. Assuming that the line's endpoints are (x₁, y₁) and (x₂, y₂), the midpoint (a, b) is determined using the following formula:
(a , b) ≡ (((x₁ + x₂)/2), ((y₁ + y₂)/2))
Let the line segment be AB having endpoints as A(4, 2) and B(7, 6);
also let the co-ordinates of midpoint be C = (a, b)
Using the given formula in the available literature,
(a, b) = ((4 + 7)/2, (2 + 6)/2)
Equating parts of the previous equation, we get,
a = (4 + 7)/2 = 11/2 = 5.5
b = (2 + 6)/2 = 4
Thus, the midpoint of the segment is (5.5, 4).
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Answer: 11.31372
Step-by-step explanation:
- Find the height using pythagorean theorem
1+b^2=9
you should get radical 8
2. Then plug your values into the formula and you get your answer
120 a month (1250-650 = 600, 600 divided by 5 = 120)
Answer:
Let's talk through this a one step at a time.
*Since f(x) is concave-up with its vertex on the x-axis, we know f(x) ≥ 0.
*We also know that when we shift a function's domain by a positive number, we shift the function left and when we shift a function's domain by a negative number, we shift the function right. So f(x-5) is f(x) shifted to the right by 5.
*At this point, f(x-5) has its vertex at (5,0).
*When we negate f(x-5), the parabola becomes concave down yet the vertex remains at (5,0). Now we're at -f(x-5). At this point we have -f(x-5)≤0 with a range (-∞,0]
*If we add 2 to create g(x)=2-f(x-5), then we have a concave down parabola with its vertex shifted up by 2, at (5,2). So, g(x) is concave down with its vertex at (5,2). Hence
