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Ainat [17]
3 years ago
8

the product of 8 and the sum of 4 and a number is 112. What is the number? Which equation could be used to solve for the number?

Mathematics
2 answers:
Akimi4 [234]3 years ago
4 0
Product of 8 and the sum of 4 and a number:

sum of 4 and a number: (4 + n)

Product of 8

8 x (4 + n) is 112

8 x (4 + n) = 112

Distribute

32 + 8n = 112

Subtratc

8n = 80

Divide by 8

n = 10

The number is 10, and next time please put options because it says "Which equation could be used to solve for the number?" Thanks! :)
lozanna [386]3 years ago
3 0

Answer:

x=10

8(4+x) = 112

Step-by-step explanation:

the product of 8 and the sum of 4 and a number is 112

LEt x be the unknown number

the sum of 4 and a number  

Sum means addition, so we add 4 and x

4+x

product of 8 and sum 4+x

product means multiplication

8(4+x)

8(4+x) is equal to 112

8(4+x) = 112 is the equation used to solve for the number

We solve for x

32 + 8x = 112

Subtract 32 on both sides

8x=80

divide by 8 on both sides

x=10

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8 0
2 years ago
A fair die is rolled 10 times. Find the expected value of:a) the sum of the numbers in the ten rolls;b) the number of multiples
velikii [3]

Answer:

a) 3.5

b) 3.33

c) 6 - 6\left(\begin{array}{ccc}5\\6\end{array}\right)^{10}

Step-by-step explanation:

As given,

A fair die is rolled 10 times

a)

Expected value of Sum of the number in 10 rolls = \frac{1}{6}(1+2+3+4+5+6) = \frac{21}{6}

                                                                                = 3.5

∴ we get

Expected value of Sum of the number in 10 rolls = 3.5

b)

Ley Y : number of multiples of 3

Y be Binomial

Y - B(n = 10, p = \frac{2}{6} )

Now,

Expected value = E(Y) = np = 10×\frac{2}{6}  = 3.33

c)

Let m = total number of faces in a die

⇒m = 6

As die is roll 10 times

⇒n = 10

Now,

Let Y = number of different faces appears

Now,

Expected value, E(Y) = m - m\left(\begin{array}{ccc}m-1\\m\end{array}\right)^{n}

                                  = 6 - 6\left(\begin{array}{ccc}6-1\\6\end{array}\right)^{10} = 6 - 6\left(\begin{array}{ccc}5\\6\end{array}\right)^{10}

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2 years ago
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