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allsm [11]
1 year ago
7

Determine the area of figure round to the nearest tenth if necessary..

Mathematics
1 answer:
qwelly [4]1 year ago
3 0
\begin{gathered} A1=\frac{4ft\cdot3ft}{2} \\ A1=6ft^2 \\  \\ A2=\frac{5ft\cdot6ft}{2} \\ A2=15ft^2 \\  \\ AT=A1+A2 \\ AT=6ft^2+15ft^2 \\ AT=21ft^2 \end{gathered}

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What is the value for ƒ(x) = 42x - 100 when x = 2 ?
Anton [14]
F(2)=42(2)-100
f(2)= -16
f(2)/-16= -8
3 0
3 years ago
Please help me on this ! only the circled ones btw.
timurjin [86]
Knobibibuvuguguvuhhh
3 0
3 years ago
In the given figure, find m∠RST, if m∠RSU = 43º and m∠UST = 23º.
pickupchik [31]

Applying the angle addition postulate, the measure of angle RST is: 66°.

<h3>What is the Angle Addition Postulate?</h3>

If two angles share a common vertex and a common side, they are adjacent angles that form a larger angle. According to the angle addition postulate, the sum of these two adjacent angles will give a sum that is equal to the measure of the larger angle they both form.

We know the following:

Measure of angle RSU = 43º

Measure of angle UST = 23º

In the diagram given, angle RSU and angle UST are adjacent angles that form a larger angle, angle RST.

Therefore, based on the angle addition postulate, the measure of angle RST = sum of the measures of angles RSU and UST.

Therefore, we would have:

m∠RST = m∠RSU + m∠UST

Substitute

m∠RST = 43 + 23

m∠RST = 66°

Learn more about the angle addition postulate on:

brainly.com/question/24746945

#SPJ1

8 0
1 year ago
birth weights in norway are normally distributed with a mean of 3570 g and a standard deviation of 500g. if the hospital officia
Svetradugi [14.3K]

Answer:

2630 g

Step-by-step explanation:

From the given information:

Given that:

mean (μ) = 3750 g

Standard deviation (σ) = 500

Suppose the hospital officials demand special treatment with a percentage of  lightest 3% (0.03) for newborn babies;

Then, the weight of birth that differentiates the babies that needed special treatment from those that do not can be computed as follows;

P(Z < z₁) = 0.03

Using the Excel Formula; =NORMSINV(0.03) = -1.88

z₁ = - 1.88

Using the test statistics z₁ formula:

z_1 = \dfrac{X-\mu}{\sigma}

-1.88 = \dfrac{X-3570}{500}

By cross multiply, we have:

-1.88 × 500 = X - 3570

-940 = X - 3570

-X = -3570 + 940

-X = -2630

X = 2630 g

Hence, 2630 g is the required weight of birth   that differentiates the babies that needed special treatment from those that do not

6 0
3 years ago
Please assist me with this problem
Sholpan [36]

2.1 X 4.4 - 3.6 / 0.4

9.24 - 9

0.24

Hope this helps! ;)

7 0
4 years ago
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