Ask question

Ask question

All categories

1 year ago

7

Determine the area of figure round to the nearest tenth if necessary..

1 answer:

qwelly [4]1 year ago

3 0

$\begin{gathered} A1=\frac{4ft\cdot3ft}{2} \\ A1=6ft^2 \\ \\ A2=\frac{5ft\cdot6ft}{2} \\ A2=15ft^2 \\ \\ AT=A1+A2 \\ AT=6ft^2+15ft^2 \\ AT=21ft^2 \end{gathered}$

You might be interested in

If a pine tree grows 3 inches per year,how long will it take for the tree to reach a height of 8 feet

vichka [17]

Answer:

32 years

Step-by-step explanation:

8x12 because there are 12 inches in a foot

8x12=96

96/3

96/3=32

4 0

2 years ago

Read 2 more answers

The height of the tunnel at the center is 35ft, and the vertical clearance must be 21 ft at a point of 8ft from the center. Find

Zinaida [17]

Answer:

y=-0.215x^2+35

Step by Step:

Let, $h=0$ , $k=35$ , $x=8$ , $y=21$

We know that, the general equation of the parabola.

$y-k = a(x-h)^2$

$\Rightarrow y=a(x-h)^2+k .........(i)$

Substitute the value of $h, k, x, y$ in equation $(i)$ and find the value of $a.$

$21=a(8-0)^2+35$

$\Rightarrow 21=a\times 8^2+35$

$\Rightarrow 21=64a+35$

$\Rightarrow 64a=21-35$

$\Rightarrow 64a=-14$

$\Rightarrow a=\frac{-14}{65}$

$\Rightarrow a=-0.215$

Hence, the equation of the parabola is:

$y=-0.215x^2+35$

8 0

3 years ago

I WILL GIVE BRAINLEST IF YOU ANSWER BOTH WITH EXPLANATION please dont let me fail :(

Lapatulllka [165]

I see grey but if that’s black okay.
2/5

You had a 2/5 chance
He had a 1/4 chance

8 0

3 years ago

Read 2 more answers

10-root18/root2 = a+broot2

Sauron [17]

Step-by-step explanation:

$\frac{10 - \sqrt{18} }{ \sqrt{2} } = a + b \sqrt{2}$

$\frac{10}{ \sqrt{2} } + \frac{ - \sqrt{18} }{ \sqrt{2} }$

$5 \sqrt{2} + ( \frac{ - \sqrt{18} }{ \sqrt{2} } ) \times \sqrt{2}$

$a = 5 \sqrt{2}$

$b = \frac{ - \sqrt{18} }{ \sqrt{2} }$

8 0

2 years ago

When asked to find a number one-tenth as large as another number, what operation would you use? What about when asked to find a

marishachu [46]

That's question is unknown

8 0

3 years ago