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anzhelika [568]
3 years ago
13

10-root18/root2 = a+broot2

Mathematics
1 answer:
Sauron [17]3 years ago
8 0

Step-by-step explanation:

\frac{10 -  \sqrt{18} }{ \sqrt{2} } = a + b \sqrt{2}

\frac{10}{ \sqrt{2} }   +  \frac{ -  \sqrt{18} }{ \sqrt{2} }

5 \sqrt{2}   + (  \frac{ -  \sqrt{18} }{ \sqrt{2} } ) \times  \sqrt{2}

a = 5 \sqrt{2}

b =  \frac{ -  \sqrt{18} }{ \sqrt{2} }

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Between 1965 and 1980, the world population grew at an annual rate of 2%. Using the rule of 72, population is expected to double
Fiesta28 [93]

Answer:

The population is expected to double in 36 years

Step-by-step explanation:

According to the the rule of 72,

A value is doubled if the product of the annual rate and number of years is 72,

Given,

The annual rate of interest = 2%

Let x be the time in years after 1965,

By the above statement,

The population will double if,

x × 2 = 72 ⇒ x = 36

Hence, the after 36 years since 1965 the population will be doubled,

i.e in 2001.   ( ∵ 36 years after 1965 )

4 0
4 years ago
Prove that:- (1-sinA)(1+sinA)÷(1+cosA)(1-cosA)=cot^2A​
astraxan [27]

Answer:

see explanation

Step-by-step explanation:

Using the trigonometric identity

sin²x + cos²x = 1 , then

sin²x = 1 - cos²x and cos²x = 1 - sin²x

Consider the left side

\frac{(1-sinA)(1 + sinA)}{(1+cosA)(1-cosA)} ← expand numerator/denominator using FOIL

= \frac{1-sin^2A}{1-cos^2A}

= \frac{1-(1-cos^2A)}{1-(1-sin^2A)}

= \frac{1-1+cos^2A}{1-1+sin^2A}

= \frac{cos^2A}{sin^2A}

= cot²A = right side , thus proven

6 0
3 years ago
Find the anhle measure x in the figure​
Margarita [4]

Answer:

x=25°

Step-by-step explanation:

<u>Sum of angles of a triangle equals 180°</u>

  • x + 10° + 2x + 15° + 3x + 5° = 180°
  • 6x + 30° = 180°
  • 6x = 180° - 30°
  • 6x = 150°
  • x = 150°/6
  • x = 25°
5 0
3 years ago
I needa know how to do this
Elena L [17]

Answer:

So I (3,0) becomes I' (1,3)

H (5,2) H' (1,1)

G (2,4) G' (2,1)

Step-by-step explanation:

So let's start with I, just count how many times you move to the left then how many times you move up.

UR WELCOME BABEEEE~ <3

5 0
3 years ago
When finding the 9th term in a geometric sequence with a common ratio of 2 and a first
Zarrin [17]

Answer:

8

Step-by-step explanation:

Nth term of a geometric sequence is given as:

t_n = a r^{(n-1)} ...(1)

Plugging n = 9, a = 3 and r = 2 in the above equation, we find:

t_9 = (3) (2)^{9-1}

t_9 = (3) (2)^{8}... (2)

Comparing equations (1) & (2), we obtan:

(n - 1) = 8

5 0
3 years ago
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