10-root18/root2 = a+broot2

Mathematics

1 answer:

Sauron [17]3 years ago

8 0

Step-by-step explanation:

$\frac{10 - \sqrt{18} }{ \sqrt{2} } = a + b \sqrt{2}$

$\frac{10}{ \sqrt{2} } + \frac{ - \sqrt{18} }{ \sqrt{2} }$

$5 \sqrt{2} + ( \frac{ - \sqrt{18} }{ \sqrt{2} } ) \times \sqrt{2}$

$a = 5 \sqrt{2}$

$b = \frac{ - \sqrt{18} }{ \sqrt{2} }$

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NO LINKS!!!! Find the equation of the circle below

inysia [295]

Answer:

$(x+3)^2+(y-2)^2=9$

Step-by-step explanation:

Equation of a circle

$(x-a)^2+(y-b)^2=r^2$

where:

(a, b) is the center
r is the radius

From inspection of the diagram, the center of the circle appears to be at point (-3, 2), although this is not very clear. Therefore, a = -3 and b = 2.

Substitute these values into the general form of the equation of a circle:

$\implies (x-(-3))^2+(y-2)^2=r^2$

$\implies (x+3)^2+(y-2)^2=r^2$

Again, from inspection of the diagram, the maximum vertical point of the circle appears to be at y = 5. Therefore, to calculate the radius, subtract the y-value of the center point from the y-value of the maximum vertical point:

⇒ radius (r) = 5 - 2 = 3

Substitute the found value of r into the equation:

$\implies (x+3)^2+(y-2)^2=3^2$