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iogann1982 [59]
1 year ago
11

What is the approximate value for 813 divided by 13 A. 30 B. 35 C. 40 D. 45

Mathematics
1 answer:
kirill115 [55]1 year ago
7 0

None of the options is correct. 813 divided by 13 equals 62.538461, whose approximate value is 62

13 times 813 equals 62.538461.

813/13 produces a non-terminating, repeating decimal as a consequence.

The repeating pattern seen above, 538461, is referred to as repetend and is shown with an overline and vinculum.

Another typical parenthetical remark is this one: 813/13 = 62.(538461): However, it's likely that you may see the reptend marked with an ellipsis in daily use: 813 / 13 = 62.538461… .

Decimal 813 divided by 13 equals 62.538461.

In a fraction, 813 is equal to 813/13.

To learn more about division from given link

brainly.com/question/892642

#SPJ9

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What is the slope of line that passes through the points (-3,8) and (1,32)?​
larisa [96]

Answer:

6

Step-by-step explanation:

use the formula of slopes

=  \frac{y2 - y1}{x2 - x1}  \\  =  \frac{32 - 8}{1 - ( - 3)}  \\   = \frac{24}{4}  \\  = 6

8 0
3 years ago
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Evaluate the dot product of (2,4) and (1,2)
Aleksandr [31]

ANSWER

The dot product is 10.

EXPLANATION

The given vectors are (2,4) and (1,2).

If we have the vectors

u=(a,b) and v=(c,d)

Then the dot product of the two vectors is given by

u \bullet \: v = ac + bd

This implies that,

(2,4)  \bullet(1,2) = 2 \times 1 + 4 \times 2

This simplifies to;

(2,4)  \bullet(1,2) = 2  + 8 = 10

4 0
3 years ago
Two planes start flying towards each other simultaneously from two different cities. The distance between the cities is 960 mile
ANTONII [103]

Answer:

257.5 mph

332.5 mph

Step-by-step explanation:

The initial distance between the two planes is 960 miles, while the final distance (after t=1.5 h) is 75 miles, so the total distance covered by the two planes in 1.5h is

d=960-75=885 miles

Calling v1 and v2 the velocities of the two planes, we have the following equations:

(1) v_1 = v_2 + 75 --> velocity of plane 1 exceeds velocity of plane 2 by 75 mph

(2) v_1 t+ v_2 t=885 --> the total distance covered by the two planes is 885 miles (t=1.5 h is the time, and the products v1 t and v2 t represent the distance covered by each plane)

Substituting t=1.5 h, the second equation becomes:

1.5 v_1+1.5 v_2=885\\v_1 + v_2 = 590

By substituting (1) into this last equation, we find:

(v_2+75)+v_2 = 590\\2v_2 + 75 = 590\\2v_2 = 515\\v_2=257.5

And substituting this back into eq.(1), we find

v_1 = 257.5 + 75=332.5

So, the speeds of the two planes are

257.5 mph

332.5 mph



3 0
3 years ago
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brilliants [131]

Answer:

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Step-by-step explanation:

using ac method

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Irina-Kira [14]

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6 0
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