You can see that every decade the income increases by 6,250. So if you want to do 5 years instead you would have to add 3,125 to the income of 1980 to find what the income was for 1985. Now you add 33,750+3,125= 36,875. The financial aid cutoff for 1985 would be $36,875.
Sample space ={5G, 2Y, 8R, 3P} =18 POSSIBLE OUTCOME
1st draw: P(R) = 8/18 = 4/9 = 0.444
2nd draw (no replacement, means already one Red is picked up, so the sample space has been reduced): P(another one more RED) = 7/17 =0.411
![\bf -7x-2y=4\implies -2y=7x+4\implies y=\cfrac{7x+4}{-2}\implies y=\cfrac{7x}{-2}+\cfrac{4}{-2} \\\\\\ y=\stackrel{\stackrel{m}{\downarrow }}{-\cfrac{7}{2}} x-2\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20-7x-2y%3D4%5Cimplies%20-2y%3D7x%2B4%5Cimplies%20y%3D%5Ccfrac%7B7x%2B4%7D%7B-2%7D%5Cimplies%20y%3D%5Ccfrac%7B7x%7D%7B-2%7D%2B%5Ccfrac%7B4%7D%7B-2%7D%20%5C%5C%5C%5C%5C%5C%20y%3D%5Cstackrel%7B%5Cstackrel%7Bm%7D%7B%5Cdownarrow%20%7D%7D%7B-%5Ccfrac%7B7%7D%7B2%7D%7D%20x-2%5Cqquad%20%5Cimpliedby%20%5Cbegin%7Barray%7D%7B%7Cc%7Cll%7D%20%5Ccline%7B1-1%7D%20slope-intercept~form%5C%5C%20%5Ccline%7B1-1%7D%20%5C%5C%20y%3D%5Cunderset%7By-intercept%7D%7B%5Cstackrel%7Bslope%5Cqquad%20%7D%7B%5Cstackrel%7B%5Cdownarrow%20%7D%7Bm%7Dx%2B%5Cunderset%7B%5Cuparrow%20%7D%7Bb%7D%7D%7D%20%5C%5C%5C%5C%20%5Ccline%7B1-1%7D%20%5Cend%7Barray%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
now, what's the slope of a line parallel to that one above? well, parallel lines have exactly the same slope.
Move the expression around so variables are with variables and numbers with numbers: 5/6p-2/3p+1/5-1
create a common denominator for variables and numbers: 5/6p-4/6p+1/5-5/5
simplify: 1/6p-4/5
I have 2 cookies and 5 friends, how much of the cookies do each of my friends get?
