The value of the given trigonometry function is 2√15/15
<h3>Half angles</h3>
Half angles are trigonometric identities used to express sine, cosine and tangent of half angles.
For instance the value of cos theta is expressed as shown below;
cosФ = cos(Ф/2+Ф/2)
cosФ = cos²Ф/2-sin²Ф/2
cosФ = cos²Ф/2-(1-cos²Ф/2)
cosФ = 1 - 2cos²Ф/2
Given the following parameters
cosФ = -7/15
Substitute
cosФ = 1 - 2cos²Ф/2
-7/15 = 1 - 2cos²Ф/2
-2cos²Ф/2 = -7/15 - 1
-2cos²Ф/2 = -8/15
cos²Ф/2 = 4/15
cosФ/2 = 2/√15
Rationalize
2/√15 * √15/√15
2√15/15
Hence the value of the given trigonometry function is 2√15/15
Learn more on trigonometry function here: brainly.com/question/2254074
#SPJ1
The answer is the first option: Even.
The explanation for this exercise is shown below:
1. By definition, if
the fucntion is even.
2. When the graph is symmetric with respect to the y-axis, it is an even function.
3. As you you can see in the graph attached in the problem, the graph is symmetric about the y-axis. Therefore, you can conclude it is an even function.
Answer:
Choice 3: AAS
Step-by-step explanation:
We can prove that by AAS that means we need two congruent angles and one congruent side.
The first angle will be the vertical pair <FBG and <DBC.
The second angle will be the alternate interior pair <G and <D.
The one side will be
and
.
Answer:
Step-by-step explanation:
pop 1 n₁ = 260, p₁ = 58% = 0.58
pop 2 n₂ = 260, p₂ = 8% = 0.08
Null hypothesis: p₁ ≤ p₂
Alternative hypothesis: p₁ > p₂
The test statistic : p₁-p₂ / √{p-sample (1 - p-sample) (1/n₁ + 1/n₂)}
where p-sample is sample proportion = p₁n₁ +p₂n₂ / n₁+n₂
Thus, p-sample = 0.58x260 +0.08x260 / 260+260 =150.8+20.8 / 520 = 171.6 / 520 = 0.33.
Thus, the test statistic is (0.58 - 0.08) / √[0.33 (1-0.33) (0.0038+0.0038)
= 0.5 / √[0.33(0.67) (0.0076)
= 0.5 / √0.00168036
= 0.5 / 0.04099
= 12.20
P = P(Z>12.20) = 1-P(Z≤12.20) at a significance level of 0.1= the p-value is less than the hypothesized thus, we have sufficient evidence to reject the null hypothesis and concluding that vinyl gloves have a greater virus leak than latex gloves.