Answer:
Therefore,
![r=\sqrt[3]{\frac{3V}{4\pi }}](https://tex.z-dn.net/?f=r%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B3V%7D%7B4%5Cpi%20%7D%7D)
is the required r
Step-by-step explanation:
Given:
Volume of inside of the sphere is given as
![V=\frac{4}{3} \pi r^{3}](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B4%7D%7B3%7D%20%5Cpi%20r%5E%7B3%7D)
where r is the radius of the sphere
To Find:
r =?
Solution:
We have
......Given
![3\times V=4\pi r^{3} \\\\\therefore r^{3}=\frac{3V}{4\pi } \\\\\therefore r=\sqrt[3]{\frac{3V}{4\pi }} \textrm{which is the expression for r}](https://tex.z-dn.net/?f=3%5Ctimes%20V%3D4%5Cpi%20r%5E%7B3%7D%20%5C%5C%5C%5C%5Ctherefore%20r%5E%7B3%7D%3D%5Cfrac%7B3V%7D%7B4%5Cpi%20%7D%20%5C%5C%5C%5C%5Ctherefore%20r%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B3V%7D%7B4%5Cpi%20%7D%7D%20%5Ctextrm%7Bwhich%20is%20the%20expression%20for%20r%7D)
Therefore,
![r=\sqrt[3]{\frac{3V}{4\pi }}](https://tex.z-dn.net/?f=r%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B3V%7D%7B4%5Cpi%20%7D%7D)
is the required r
The answer is fifteen yards
Answer:
![\sf A) \ (-4, \ 0) \ and \ \ [\dfrac{5}{2} , \ 0]](https://tex.z-dn.net/?f=%5Csf%20A%29%20%5C%20%28-4%2C%20%5C%200%29%20%5C%20and%20%5C%20%5C%20%20%5B%5Cdfrac%7B5%7D%7B2%7D%20%2C%20%5C%200%5D)
Explanation:
Given function: f(x) = -2x² - 3x + 20
To find the x-intercepts of a function, f(x) = 0
=================
-2x² - 3x + 20 = f(x)
-2x² - 3x + 20 = 0
-2x² - 8x + 5x + 20 = 0
-2x(x + 4) + 5(x + 4) = 0
(-2x + 5) (x + 4) = 0
-2x + 5 = 0, x + 4 = 0
-2x = -5, x = -4
x = -5/-2,x = -4
x = 5/2, x= -4
Coordinates: (-4, 0), (5/2, 0)
Of 5 out of 12 (5/12) are sports games and 3 out of 12 (3/12) are educational, then you would add these together because you need a total for both because it would include one or the other, so both.
5/12 + 3/12= 8/12 or 2/3 are one or the other.