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Simora [160]
1 year ago
11

Betty has several of the standard six-sided dice that are common in many board games. If Betty rolls one of these dice, what is

the probability that: She rolls a 6
Mathematics
1 answer:
s344n2d4d5 [400]1 year ago
5 0

Answer:

the probabillty is 6

Step-by-step explanation:

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What is the sum of the geometric sequence -4, 24, -144... if there are 10 terms?
grandymaker [24]

Answer:

34552100

Step-by-step explanation:

Sum=a(r^n-1)/(r-1)=-4*((-6)^n)-1)/(-6-1)=-4*((-6)^10)-1)/(-7)=34552100

Solved by gauthmath.

7 0
3 years ago
A quality control officer is randomly checking the weights of pumpkin seed bags being filled by an automatic filling machine. Ea
grandymaker [24]
If a bag of pumpkin seeds must weigh within 2.1 grams in order to be accepted, each bags must weigh between (400-2.1) grams and (400+2.1) grams. This means that if a bag weighs less than 397.9 grams (x<397.9) or more than 402.1 grams (x>402.1) it will be rejected. Therefore, 397.9>x>402.1 is the range of rejected bags.
8 0
3 years ago
Read 2 more answers
The mass of a freight train is 9.98 ⋅ 106 kilograms. The mass of an aircraft carrier is 7.3 ⋅ 107 kilograms. Approximately how m
shutvik [7]
Mass of freight train: 9.98 • 106
= 1057.88 kg
mass of aircraft carrier: 7.3 • 107
= 781.1 kg
difference: 1057.88 - 781.1
= 276.78 kg
= 2.7678 x 10^2
8 0
2 years ago
Question 1
vivado [14]

Answer:

For Lin's answer

Step-by-step explanation:

When you have a triangle, you can flip it along a side and join that side with the original triangle, so in this case the triangle has been flipped along the longest side and that longest side is now common in both triangles. Now since these are the same triangle the area remains the same.

Now the two triangles form a quadrilateral, which we can prove is a parallelogram by finding out that the opposite sides of the parallelogram are equal since the two triangles are the same(congruent), and they are also parallel as the alternate interior angles of quadrilateral are the same. So the quadrilaral is a paralllelogram, therefore the area of a parallelogram is bh which id 7 * 4 = 7*2=28 sq units.

Since we already established that the triangles in the parallelogram are the same, therefore their areas are also the same, and that the area of the parallelogram is 28 sq units, we can say that A(Q)+A(Q)=28 sq units, therefore 2A(Q)=28 sq units, therefore A(Q)=14 sq units, where A(Q), is the area of triangle Q.

7 0
3 years ago
Read 2 more answers
An expression is shown below: 2x3y + 18xy − 10x2y − 90y Part A: Rewrite the expression by factoring out the greatest common fact
SCORPION-xisa [38]

Answer:

Part A : 2y( x³ + 9x - 5x² - 45 ), Part B : 2y( x - 5 )( x² + 9 )

Step-by-step explanation:

Part A : Let's break every term down here to their " prime factors ", and see what is common among them,

2x³y + 18xy − 10x²y − 90y -

2x³y  = 2 * x³ * y,

18xy = 2 * 3 * 3 * x * y,

− 10x²y = 2 * - 5 * x² * y, - so as you can see for this example I purposely broke down - 10 into 2 and - 5. I could have placed the negative on the 2, but as that value was must likely common among all the terms, I decided to place it on the 5. The same goes for " − 90y. " I placed the negative there on the 5 once more.

− 90y = 2 * - 5 * 3 * 3 * y

The terms common among each term are 2 and y. Therefore, the GCF ( greatest common factor ) is 2x. Let's now factor the expression using this value.

2y( x³ + 9x - 5x² - 45 )

Part B : Let's simply factor this entire expression. Of course starting with the " factored " expression : 2y( x³ + 9x - 5x² - 45 ),

2y\left(x^3+9x-5x^2-45\right) - Factor out " (x^3+9x-5x^2-45\right)) " by grouping,

\left(x^3-5x^2\right)+\left(9x-45\right) - Factor 9 from 9x - 45 and x² from x³ - 5x²,

9\left(x-5\right)+x^2\left(x-5\right) - Factor out common term x - 5,

\left(x-5\right)\left(x^2+9\right) - And our solution is thus 2y( x - 5 )( x² + 9 )

3 0
3 years ago
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