If theres on at all then ~ C 6-8 however it seems that theres not one tbh
7x - 3(-2) = 23
7x - - 6 = 23 (two minuses make a plus)
so it’s gonna be 7x + 6 = 23
Now you have isolate you x, so move everything else to the other side, but remember to change your sign when transferring to the other side
7x = 23 - 6
7x = 17
To isolate x in this multiple, you divide by 7 (because the inverse of multiplication is division)
x = 17/7
Let us compute first the probability of ending up an odd number when rolling a dice. A dice has faces with numbers 1 up to 6. The odd numbers within that is 3 (1, 3 and 5). Therefore, each dice has a probability of 3/6 or 1/2. Then, you use the repeated trials formula:
Probability = n!/r!(n-r)! * p^r * q^(n-r), where n is the number of tries (n=6), r is the number tries where you get an even number (r=0), p is the probability of having an even face and q is the probability of having an odd face.
Probability = 6!/0!(6!) * (1/2)^0 * (1/2)^6
Probability = 1/64
Therefore, the probability is 1/64 or 1.56%.
Answer:
The remaining 15 athletes did not participate in any type of flexibility program