So, let's look at the problem once again.
8%, or 8/100 of the bag were green jelly beans.
Let's see what we can do to find out a number of other jelly beans, not including the green ones.
We know that 92% of jelly-beans are not green.
92% is 11.5 times more than 8%
(92/8)
24 (or 8%) times 11.5 = 276
276 - number of jelly beans that are not green.
276 plus 24 = 300.
Answer: 300 jelly beans were in one bag.
Answer:
1. Answer is C
4. Answer is G
Step-by-step explanation:
I'm not sure how to explain 1 since I used a calculator.
Number 4 is where you choose a point on the line and count 4 blocks up and 5 blocks left. If it hits another point on the line then that's the graph.
Answer:
I don't get it
Step-by-step explanation:
Answer:
AC ≈ 5.03
Step-by-step explanation:
We can solve the problem above using the trigonometric ratio, they are;
SOH CAH TOA
sin Ф = opposite / hypotenuse
cosФ= adjacent/ hypotenuse
tan Ф = opposite / adjacent
From the diagram above, in reference to angle B;
opposite =AC and adjacent =BC
Since we have opposite and adjacent, the best formula to use is
tanФ = opposite / adjacent
tan B = AC / BC
tan 40 = AC/ 6
Multiply both-side of the equation by 6
6× tan 40 = AC/ 6 × 6
At the right-hand side of the equation, 6 will cancel-out 6 leaving us with just AC
6×tan 40 = AC
5.034598 = AC
AC ≈ 5.03 to the nearest hundredths
Answer:
The total number of ways are 168.
Step-by-step explanation:
Consider the provided information.
There are 7 junior and 3 senior coders in her group.
The first project can be written by any of the coders. The second project must be written by a senior person and the third project must be written by a junior person.
For second project we have 3 choices and for third project we have 7 choices.
Now there are 2 possible case:
Case I: If first and second coder is senior, then the total number of ways are:
Case II: If first and third coder is junior, then the total number of ways are:
Hence, the total number of ways are: 42+126=168
