Question

Given f(x) = 4x3 − 12x2 + 40x + 12, find f(–2). A) f(–2) = –52 B) f(–2) = –96 C) f(–2) = –108 D) f(–2) = –148

Answer 1

Given function : $f(x) = 4x^3 -12x^2 + 40x + 12$.

We need to find the values of f(-2).

In order to find the value of f(-2), we need to plug x=-2 in the given fucntion $f(x) = 4x^3 -12x^2 + 40x + 12$.

Replacing x by -2, we get

$f(-2) = 4(-2)^3 -12(-2)^2 + 40(-2) + 12$

We get (-2)^2 = -2 *-2*-2=-8 and (-2)^2 = -2 * -2 = 4.

$f(-2) = 4(-8) -12(4) +40(-2) +12$ .

$f(-2) = -32 -48 -80+12.$

f(-2) = -160 +12.

f(-2) = -148.

Therefore, correct option would be option D. That is  f(-2)=-148.