Answer:
Step-by-step explanation:
Since this is an improper fraction, you simplify it into a mixed number.
4 goes into 6 1 time. 2 left left over, resulting in 1 2/4. Simplify that into
1 1/2
Answer:
Statement 2 (The ages of the Stars are the most dispersed from the team’s mean).
Step-by-step explanation:
Standard deviation is one way to measure the average of the data by determining the spread of the data. It actually explains how much the observation points are further away from the mean of the data. Higher the standard deviation, higher the spread of the data and higher is the uncertainty. This means that the team with the highest standard deviation will have the most dispersion. In this case, the standard deviation of 4.1 is the largest number, therefore, the statement "The ages of the Stars are the most dispersed from the team’s mean." is true i.e. the option 2!!!
Mean:
E[Y] = E[3X₁ + X₂]
E[Y] = 3 E[X₁] + E[X₂]
E[Y] = 3µ + µ
E[Y] = 4µ
Variance:
Var[Y] = Var[3X₁ + X₂]
Var[Y] = 3² Var[X₁] + 2 Covar[X₁, X₂] + 1² Var[X₂]
(the covariance is 0 since X₁ and X₂ are independent)
Var[Y] = 9 Var[X₁] + Var[X₂]
Var[Y] = 9σ² + σ²
Var[Y] = 10σ²
40 below 0 would be -40 and 20 below 0 would be -20°. So there’s a change of (increase of) 20° that day. It would also make sense if you drew a number line. You would see the interval between -40 and -20 is 20.
