each term of a sequence is 2 more than the previous term. if the third term is 8 find the first five terms of the sequence
1 answer:
Step-by-step explanation:
T3=8
8=a+2d
where a is first term ,d is common ratio
8=a+2(2)
8=a+4
a=8-4
a=4
first term T1 is 4
T2=a+d
T2=4+2
T2=6
T4=a+3d
T4=4+3(2)
T4=4+6
T4=10
T5=a+4d
T5=2+4(2)
T5=4+8
T5=12
4,6,8,10,12
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you can use formular method or factorisation but formular method is easy and convinient
He means that 5.08 cm is a possible coordinate, and 50.8 mm is a possible coordinate
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C. 25
——-
Divide 400/100=4
——-
Than divide 4/100
—-
22/22-12/22= 10/22
Which can be simplified as 5/11