each term of a sequence is 2 more than the previous term. if the third term is 8 find the first five terms of the sequence
1 answer:
Step-by-step explanation:
T3=8
8=a+2d
where a is first term ,d is common ratio
8=a+2(2)
8=a+4
a=8-4
a=4
first term T1 is 4
T2=a+d
T2=4+2
T2=6
T4=a+3d
T4=4+3(2)
T4=4+6
T4=10
T5=a+4d
T5=2+4(2)
T5=4+8
T5=12
4,6,8,10,12
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