First, let's identify some variables:
d = dress price
s = shirt price
d = 3s
12s + d = 450
Because d = 3s, we can substitute the variable:
12s + 3s = 450
15s = 450
s = 30
The shirt costs $30, and the dress $10
Answer:
0.88
Step-by-step explanation:
P(x≥2) = P(x=2) + P(x=3) + P(x=4) + P(x=5) + P(x=6)
P(x≥2) = 0.21 + 0.35 + 0.21 + 0.06 + 0.05
P(x≥2) = 0.88
Or, you can calculate it as:
P(x≥2) = 1 - P(x=1) - P(x=0)
P(x≥2) = 1 - 0.09 - 0.03
P(x≥2) = 0.88
Answer:
See below
Step-by-step explanation:
<h3>Graphing:</h3>
we are given two functions
where f(x) is a <em>linear</em><em> </em><em>function</em> and g(x) is a <em>q</em><em>uadratic </em>function
we want to figure out the solutions of the function
let's graph f(x):
the Black-table is attached
let's graph g(x):
the picture is attached
hence, the graph should be
the graph is attached
<h3>solutions stating:</h3>
so we need solution(s) which satisfy(ies) the both functions
in this case the solution (s) the x coordinate(s) where both functions intercept we get from the graph that both functions intercept at <u>(</u><u>-</u><u>1</u><u>,</u><u>6</u><u>)</u> and <u>(</u><u>3</u><u>,</u><u>2</u><u>)</u>
hence,
x={-1,3}
The pair of corresponding angles have parallel lines that have to equal
Answer:
Both of these examples are wrong. You cannot add/subtract integers and square roots together, however, you could add square roots together if they have the same number under the square root. For example, 2 - 2√6 will stay as 2 - 2√6 because they aren't like terms. 25 + 5√5 + 5√5 + 5 = 30 + 10√5 because 25 + 5 = 30 and 5√5 + 5√5 = 10√5. We can add 5√5 and 5√5 together because they have the same number under the square root. If we were to compute √2 + √3, we would just leave it as is because they don't have the same number under the square root.
