Question

The state medical school has discovered a new test for tuberculosis. (If the test indicates a person has tuberculosis, the

Answer 1

The probability according to the given scenario is:

(a) 0.0395

(b) 0.95

(c) 0.076

The given values are:

• $P(B/A) = 0.79$
• $P(A) = 0.05$

(a)

The probability that the  b/w has tuberculosis as well as having (+) test will be:

→ $P(A \cap B) = P(B/A).P(A)$

By substituting the values, we get

→                  $= 0.79\times 0.05$

→                  $= 0.0395$

(b)

The probability that a person does not have tuberculosis will be:

→ $P(A') = 1-P(A)$

→            $=1-0.05$

→            $= 0.95$

(c)

The person does not have tuberculosis as well as have a (+) test, the probability will be:

→ $P(A' \cap B) = P(A').P(B/A')$

→                  $= 0.95\times 0.08$

→                  $= 0.076$

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