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Ivenika [448]
1 year ago
15

The state medical school has discovered a new test for tuberculosis. (If the test indicates a person has tuberculosis, the

Mathematics
1 answer:
Inessa [10]1 year ago
8 0

The probability according to the given scenario is:

(a) <em>0.0395</em>

(b) <em>0.95</em>

(c) <em>0.076</em>

The given values are:

  • P(B/A) = 0.79
  • P(A) = 0.05

(a)

The probability that the  b/w has tuberculosis as well as having (+) test will be:

→ P(A \cap B) = P(B/A).P(A)

By substituting the values, we get

→                  = 0.79\times 0.05

→                  = 0.0395

(b)

The probability that a person does not have tuberculosis will be:

→ P(A') = 1-P(A)

→            =1-0.05

→            = 0.95

(c)

The person does not have tuberculosis as well as have a (+) test, the probability will be:

→ P(A' \cap B) = P(A').P(B/A')

→                  = 0.95\times 0.08

→                  = 0.076

Learn more:

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