Plot a point at (0,-1)
Then from that point, go down 3 points, and to the right one point. Repeat that until you hit the bottom of the graph or run out of room. From the first point (0,-1), go up 3 and to the left 1 until you run out of room on the graph. Should be a straight line
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By using distance formula (which is attached below), you can solve this problem:
√(x2-x1)^2+(y2-y1)^2
(5, -1) and (5, 3)
√(5-5)^2+(3-(-1))^2
√0^2+4^2
√0+16
√16
4
The distance between the two points is 4.
Answer:
59%
Step-by-step explanation:
Answer: 8y4+25y3+60y2+10y+7
Step-by-step explanation:
(y2+3y+7)(8y2+y+1)
=(y2+3y+7)(8y2+y+1)
=(y2)(8y2)+(y2)(y)+(y2)(1)+(3y)(8y2)+(3y)(y)+(3y)(1)+(7)(8y2)+(7)(y)+(7)(1)
=8y4+y3+y2+24y3+3y2+3y+56y2+7y+7
=8y4+25y3+60y2+10y+7
hope this helps!:)
