Answer:
Partial pressure of oxygen = 23.38 kpa (Approx)
Explanation:
Given:
Amount of oxygen = 23.15%
Amount of nitrogen = 76.85%
Pressure (missing) = 101 kpa
Find:
Partial pressure of oxygen
Computation:
Partial pressure of oxygen = [Amount of oxygen x Pressure]/100
Partial pressure of oxygen = [23.15% x 101]/100
Partial pressure of oxygen = 23.38 kpa (Approx)
Answer:
157. 788 grams
Explanation:
number of moles = mass/molar mass.
hence the mass = molar mass × number of moles
m = 58.44 × 2.7 = 157.788 grams
1 is the answer. Both are made up of different particles. Same Letters of the periodic just not built the same ? (CO & CO2)& they are both odorless & colorless
To solve this problem we can use following equation.
v =u + at
Where v is the final velocity (m/s), u is the initial velocity (m/s), a is the acceleration (m/s²) and t is the time taken (s).
v = 7 m/s
u = 4 m/s
a = ?
t = 5 s
By applying the equation, we can get
7 m/s = 4 m/s + a x 5 s
3 m/s = a x 5 s
a = 0.6 m/s²
Hence, the acceleration is 0.6 m/s² towards north.
Answer is "C".
Answer:
Explanation:
You are not really helped by what is hold the liquid. Beakers and cylinders come on a lot of sizes. I hate to be crabby about things like that, but you really need to be aware that the question is slightly flawed (not your fault).
The beaker, you'd be like to get 1 sig digit. You have to be awfully careful about claiming more. So the and is 50 mL, but that mL is a guess and the 50 is not totally accurate, but what would you say the second digit is? 48 or 47? You don't really know. Maybe even 49.
The graduated cylinder is a little better. Read the bottom of the meniscus (the bottom of the 1/2 bubble). I think you can get 2 sig digs., so the answer is 36 mL. But everything also depends on what you have been told.
