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grandymaker [24]
2 years ago
14

Purchasing the correctly sized BMX bike is based on the height of the rider. In order to fit a customer, the salesman can use th

e equation b=0.29h+1.35 where b is the size of the BMX bike frame in inches and h is the height of the rider in inches.
1. As a rider increases one inch in height, the bike frame increases 0.29 inches.
2. The height of the rider gets multiplied by 0.29.
3. The bike frame increases 0.29 inches for every 1.35 inches of the rider's height.
4. As a rider's height increases 1.35 inches, the bike frame increases one inch.
Chemistry
1 answer:
Phantasy [73]2 years ago
5 0
Answer: Your best answer is A.

Explanation: 1.35 is a constant and thus is does not change. The equation can be simplified to-
“b = (0.29 x h)+ 1.35”
So, if your rider is say 60 inches tall, the equation would change to-
“b = (0.29 x 60)+ 1.35”
Then to-
“b = (17.4) + 1.35” or “b = 17.4 + 1.35”
And therefore the size of the BMX bike frame in inches would be-
“b = 18.75”

Hope this helped :)
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A ball is dropped from a height of 1.20 m and hits the floor. The ball compresses and then reforms to spring upwards from the fl
diamong [38]

Answer:

\large \boxed{\text{98 m$\cdot$s}^{-2}}

Explanation:

The formula for the velocity of the ball is

v = \sqrt{2gh}

1. Velocity at time of impact

v = -\sqrt{2 \times 9.807 \times 1.20} = -\sqrt{23.54} = -\textbf{4.85 m/s}

2. Velocity on rebound

The ball has enough upward velocity to reach a height of 0.86 m.

v = \sqrt{2 \times 9.807 \times 0.86} = \sqrt{16.87} =\textbf{4.11 m/s}

3. Acceleration

a = \dfrac{\Delta v}{\Delta t} = \dfrac{4.11 - (-4.85)}{ 0.091} = \dfrac{8.96 }{0.091} =\textbf{98 m$\cdot$s}^{\mathbf{-2}}\\\\\text{The acceleration while the ball is in contact with the floor is $\large \boxed{\textbf{98 m$\cdot$s}^{\mathbf{-2}}}$}

5 0
3 years ago
Isotope b has a half-life of 3 days. a scientist measures out 100 grams of this substance. after 6 days has passed, the scientis
Brilliant_brown [7]
So half life is the time taken for a sample to decay to half its original mass, its a constant and applies to any original mass, it could be 5g or 1kg, it will take the same amount of time for the original mass to half. In this case the half life is 3 days.

After 3 days the sample will be at half its original mass, now 50g. 

Now we can treat the 50g as if its a new sample. After another 3 days (6 days in total) there will be half of 50g left, = 25g. 


6 0
3 years ago
In this periodic table, which type of element is shown in green boxes?
salantis [7]

Answer: A

Explanation:

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6 0
2 years ago
If 250.0 g of water at 30.0 °C cool to 5.0 °C, how many kilojoules of energy did the water lose?
Y_Kistochka [10]

Answer:

-26.125 kj

Explanation:

Given data:

Mass of water = 250.0 g

Initial temperature = 30.0°C

Final temperature = 5.0°C

Amount of energy lost = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

ΔT = 5.0°C - 30.0°C

ΔT = -25°C

Specific heat of water is 4.18 j/g.°C

Now we will put the values in formula.

Q = m.c. ΔT

Q = 250.0 g × 4.18 j/g.°C × -25°C

Q = -26125 j

J to kJ

-26125 j ×1 kj /1000 j

-26.125 kj

5 0
3 years ago
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