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grandymaker [24]
2 years ago
14

Purchasing the correctly sized BMX bike is based on the height of the rider. In order to fit a customer, the salesman can use th

e equation b=0.29h+1.35 where b is the size of the BMX bike frame in inches and h is the height of the rider in inches.
1. As a rider increases one inch in height, the bike frame increases 0.29 inches.
2. The height of the rider gets multiplied by 0.29.
3. The bike frame increases 0.29 inches for every 1.35 inches of the rider's height.
4. As a rider's height increases 1.35 inches, the bike frame increases one inch.
Chemistry
1 answer:
Phantasy [73]2 years ago
5 0
Answer: Your best answer is A.

Explanation: 1.35 is a constant and thus is does not change. The equation can be simplified to-
“b = (0.29 x h)+ 1.35”
So, if your rider is say 60 inches tall, the equation would change to-
“b = (0.29 x 60)+ 1.35”
Then to-
“b = (17.4) + 1.35” or “b = 17.4 + 1.35”
And therefore the size of the BMX bike frame in inches would be-
“b = 18.75”

Hope this helped :)
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Consider 100.0 g samples of two different compounds consisting only of carbon and oxygen. One compound contains 27.2 g of carbon
Pani-rosa [81]

<u>Answer:</u> The ratio of carbon in both the compounds is 1 : 2

<u>Explanation:</u>

Law of multiple proportions states that when two elements combine to form two or more compounds in more than one proportion. The mass of one element that combine with a given mass of the other element are present in the ratios of small whole number. For Example: Cu_2O\text{ and }CuO

  • <u>For Sample 1:</u>

Total mass of sample = 100 g

Mass of carbon = 27.2 g

Mass of oxygen = (100 - 27.7) = 72.8 g

To formulate the formula of the compound, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{27.2g}{12g/mole}=2.26moles

Moles of Oxygen = \frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{72.8g}{16g/mole}=4.55moles

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 2.26 moles.

For Carbon = \frac{2.26}{2.26}=1

For Oxygen  = \frac{4.55}{2.26}=2.01\approx 2

  • <u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of C : O = 1 : 2

Hence, the formula for sample 1 is CO_2

  • <u>For Sample 2:</u>

Total mass of sample = 100 g

Mass of carbon = 42.9 g

Mass of oxygen = (100 - 42.9) = 57.1 g

To formulate the formula of the compound, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{42.9g}{12g/mole}=3.57moles

Moles of Oxygen = \frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{57.1g}{16g/mole}=3.57moles

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 3.57 moles.

For Carbon = \frac{3.57}{3.57}=1

For Oxygen  = \frac{3.57}{3.57}=1

<u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of C : O = 1 : 1

Hence, the formula for sample 1 is CO

In the given samples, we need to fix the ratio of oxygen atoms.

So, in sample one, the atom ratio of oxygen and carbon is 2 : 1.

Thus, for 1 atom of oxygen, the atoms of carbon required will be = \frac{1}{2}\times 1=\frac{1}{2}

Now, taking the ratio of carbon atoms in both the samples, we get:

C_1:C_2=\frac{1}{2}:1=1:2

Hence, the ratio of carbon in both the compounds is 1 : 2

8 0
3 years ago
Koja od navedenih atomskih orbitala nije moguća? a) 2d b) 3s c) 4p d) 5f​
pickupchik [31]

Answer:

2d

Explanation:

2d nije moguće. moguće je samo 3d do 7d. provjeri periodni sustav!

ako ne razumiješ, obrati mi pažnju

8 0
2 years ago
The equilibrium constant K changes with changes in<br>the temperature.​
chubhunter [2.5K]
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What is the concentration of each ion in 15.00 ml of a 7.85 X 10^-6 M solution of Tc3 (PO4)7?
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Answer:

Tc^(+7)    -    2.35*10^-5M  

PO4(^-3)  -   5.50*10^-5M

Explanation:

Tc3(PO4)7  <--->              3Tc^{7+} + 7PO_{4}^{3-}

1 mol                                3 mol      7 mol

7.85 X 10^-6 M    3*7.85*10^-6M       7*7.85*10^-6M

                            2.35*10^-5M          5.50*10^-5M

5 0
3 years ago
What does compression do?
erma4kov [3.2K]

Explanation:

Compressors and limiters are used to reduce dynamic range — the span between the softest and loudest sounds. Using compression can make your tracks sound more polished by controlling maximum levels and maintaining higher average loudness.

3 0
2 years ago
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