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Leya [2.2K]
3 years ago
15

Can someone help me answer these ?

Chemistry
1 answer:
g100num [7]3 years ago
5 0

3.3 ثنائي ميثيل الهكسان

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If the Earth had no tilt, how would that affect our seasons? I will give branliest to first comment
Aleks [24]

Answer:

in my opinion it wouldn't be regular seasons like what we have now it would be equal in every poles .. there would not be ice in North. [its my opinion though] sorry if I am wrong

6 0
3 years ago
[Send a message] as you move across a row from left to right in the period table, atomic numbers of the elements
SashulF [63]
I think it might be D or B 
And my other two might be A or C 
6 0
4 years ago
Magnesium has 12 electrons. How many electrons will be orbiting in the outermost shell, farthest away from the nucleus?
erica [24]

Answer:

Magnesium has an outer energy level of n=3 with two electrons in in its energy level. Therefor Magnesium has 2 valance electrons.

Explanation:

4 0
3 years ago
A mixture of CO2 and Kr weighs 35.0 g and exerts a pressure of 0.708 atm in its container. Since Kr is expensive, you wish to re
ollegr [7]

Explanation:

Since, it is given that carbon dioxide is completely removed by absorption with NaOH. And, pressure inside the container is 0.250 atm.

For Kr = 0.250 atm and pressure CO_{2} will be calculated as follows.

           CO_{2} = (0.708 - 0.250) atm

                       = 0.458 atm

Now, we will calculate the mole fraction as follows.

            CO_{2} = \frac{0.458}{0.708}

                       = 0.646

               Kr = \frac{0.250}{0.708}

                    = 0.353

Now, we will convert into gram fraction as follows.

              CO_{2} = 0.646 \times 44

                          = 28.424

                   Kr = 0.353 \times 83.78

                        = 29.57

Therefore, total mass is calculated as follows.

           Total mass = (28.424 + 29.57)

                              = 57.994

Hence, the percentage of CO_{2} and Kr are calculated as follows.

          CO_{2} = \frac{28.424}{57.99} \times 100

                     = 49%

               Kr = \frac{29.57}{57.99} \times 100

                    = 51%

Hence, amount of CO_{2} and Kr present i mixture is as follows.  

         CO_{2} in mixture = 35 \times 0.49

                             = 17.15 g

                  Kr = 35 \times 0.51

                       = 17.85 g

Thus, we can conclude that 17.15 g of CO_{2} is originally present and 17.85 g of Kr is recovered.

6 0
3 years ago
A physical property is a characteristic of a substance is one that _____.
saul85 [17]

A is the answer u need

8 0
4 years ago
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