Explanation:
The given data is as follows.
= 250 mL, 
= 750 mL
= 
= 35 + 273 K = 308 K
= 35 + 273 K = 308 K
= 0.55 atm, 
= 1.5 atm
P = ? , V = 10.0 L
Since, temperature is constant.
So, 
= PV
Now, putting the given values into the above formula as follows.
= PV
= 
P = 0.126 atm
As, 1 atm = 760 torr. So, 
= 95.76 torr.
Thus, we can conclude that the final pressure, in torr, of the mixture is 95.76 torr.
Answer:
992.302 K
Explanation:
V(rms) = 750 m/s
V(rms) = √(3RT / M)
V = velocity of the gas
R = ideal gas constant = 8.314 J/mol.K
T = temperature of the gas
M = molar mass of the gas
Molar mass of CO₂ = [12 + (16*2)] = 12+32 = 44g/mol
Molar mass = 0.044kg/mol
From
½ M*V² = 3 / 2 RT
MV² = 3RT
K = constant
V² = 3RT / M
V = √(3RT / M)
So, from V = √(3RT / M)
V² = 3RT / M
V² * M = 3RT
T = (V² * M) / 3R
T = (750² * 0.044) / 3 * 8.314
T = 24750000 / 24.942
T = 992.302K
The temperature of the gas is 992.302K
Note : molar mass of the gas was converted from g/mol to kg/mol so the value can change depending on whichever one you use.
C ?
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