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OleMash [197]
4 years ago
7

How would the group best find out whether their study is worth more time and resourch

Chemistry
1 answer:
Anastaziya [24]4 years ago
3 0
They would find out by studying hard and researching different things on which is more important
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Each____<br> is a female sex organ about the size and<br> shape of an almond
Galina-37 [17]

Each \sf\purple{ovary} is a female sex organ about the size and shape of an almond.

Explanation:-

  • Ovaries are the the primary female reproductive organs.
  • There are two ovaries which are located on either side of the uterus.
  • The two functions of ovaries are -i) to produce eggs (ova) and ii) to produce female hormones.

\bold{ \green{ \star{ \orange{Mystique35}}}}⋆

6 0
3 years ago
Claim The student hopes the samples are gold, which has a density of 19.3 g/cm3 . A local geologist suggested that samples might
spin [16.1K]

Answer:

Pyrite.

Explanation:

In this case, for the given samples, we compute the densities considering that the volume of each sample is computed by the difference between the volume of the water + sample and the volume of water:

\rho_1=\frac{50.25g}{(60.3-50.1)mL}=4.92g/mL\\ \\\rho_2=\frac{63.56g}{(62.5-49.8)mL}=5.01g/mL\\\\\rho_3=\frac{g}{(61.5-50.2)mL}=5.10g/mL\\\\\rho_4=\frac{55.35g}{(56.7-45.6)mL}=4.99g/mL\\\\\rho_5=\frac{74.92g}{(65.3-50.3)mL}=4.99g/mL\\\\\rho_6=\frac{67.78g}{(60.8-47.5)mL}=5.10g/mL

Therefore, since the density of the samples are closer to the density of pyrite (5.01 g/cm³) we conclude that the samples are more like to be pyrite.

Best regards.

8 0
3 years ago
Wie geht diese Aufgabe?
bogdanovich [222]

Answer:

1u1u2j2jj and her family

Explanation:

I have been 9in 7the 6same 6of 8for and then I am a solicitor at Cardiff on

3 0
3 years ago
According to the nebular theory what are asteroids and comets
Nimfa-mama [501]
Asteroids are made up of metals and rocky material , while comets are made up of ice ,dust and rocky material.   
4 0
3 years ago
Write the equilibrium constant for this reaction in terms of the equilibrium constants, Ka and Kb, for reactions a and b below:
Mars2501 [29]

Answer:

(a) Ka = \frac{(SO3)^{2} }{(S)^{2}*(O2)^{3}  }

(b) Kb = \frac{(SO2)^{1} }{(S)^{1} *(O2)^{1} }

Explanation:

Correct equation: 2S(s) + 3O_{2}(g) ⇒ 2SO_{3}(g)\\

S(s) + O_{2}(g) ⇒ 2SO_{2}(g)\\

Equilibrium constant refers to a relation between products and reactants of an equilibrium reaction with respect to the components concentration and coefficients.

generally in an equilibrium reaction between reactant A, B, C and D shown below

aA+bB ⇒ cC + dD

the equilibrium constant is represented by

k = \frac{C^{c} *D^{d} }{A^{a} *B^{b} }

comparing this with the equation in the problem the equilibrium constants ka and kb are;

Ka = \frac{(SO3)^{2} }{(S)^{2}*(O2)^{3}  }

Kb = \frac{(SO2)^{1} }{(S)^{1} *(O2)^{1} }

7 0
3 years ago
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