The derivative of given function is H’(t) = 3 – 2/t3
A derivative is a two-party contract whose value/price is derived from an underlying asset. Futures, options, forwards, and swaps are the most prevalent types
Given that H(t)= t+ 1/t^2+2t+2
We must calculate the derivative
H(t)= t+ 1/t^2+2t+2
H(t) = 3t + 1/t^2 + 2
H’(t) = d/dt(3t + 1/t^2 + 2)
H’(t) = d/dt(3t) + d/dt (1/t^2) + d/dt ( 2)
H’(t) = 3xd/dt(t) + d/dt (1/t^2) + d/dt ( 2)
H’(t) = 3xd/dt(t) + d/dt (t-2) + d/dt ( 2)
H’(t) = 3 – 2t-3
H’(t) = 3 – 2/t3
Therefore the derivative of the given function is H’(t) = 3 – 2/t3
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