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GenaCL600 [577]
1 year ago
7

4505 x 219 standard algorithm

Mathematics
1 answer:
Ymorist [56]1 year ago
4 0

After throughfall calculating the multiplication 4505 x 219 in standard algorithm, we have come to find that product is 986595

<h3>What is standard algorithm?</h3>

In elementary math, a standard algorithm or method is a particular computation technique that is typically taught for resolving particular mathematical issues. In general, these techniques include exchanging, regrouping, long division, long multiplication using a standard notation, and standard formulas for average, area, and volume.

These techniques can vary somewhat by country and time, but they typically include these techniques. Similar techniques are also available for more complex functions like square roots, but they are no longer taught in general mathematics classes because calculators are more convenient.

4505 x 219 in standard algorithm is as follows:

⇒        4 5 0 5

         <u>×    2 1 9  </u>            

        4 0 5 4 5    

    +  4 5 0 5        

  +<u> 9 0 1 0         </u>

     9 8 6 5 9 5

Learn more about standard algorithm

brainly.com/question/28819571

#SPJ9

   

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Factor completely 10xy + 3y + 20ax + 6a.
stiv31 [10]
10 xy + 3y + 20 ax + 6a = y(10x+3) + a(20x+6) = y(10x+3)+2a(10x+6)= 
(y+2a)(10x+3)
3 0
3 years ago
Read 2 more answers
Un paralelogramo con una base de 13cm y una altura de 8cm, su área es de
svlad2 [7]

El área del paralelogramo con base de 13 centímetros y altura de 8 centímetros es 104 centímetros cuadrados.

El área del paralelogramo, en centímetros cuadrados, es igual al producto de su base por su altura, ambos en centímetros. En consecuencia, el área de la figura geométrica es la siguiente:

A = (13\,cm)\cdot (8\,cm)

A = 104\,cm^{2}

El área del paralelogramo con base de 13 centímetros y altura de 8 centímetros es 104 centímetros cuadrados.

Invitamos cordialmente a ver esta pregunta sobre paralelogramos: brainly.com/question/17205536

4 0
3 years ago
Aleena expands 2xx+3-5(x-2) as 2x2+3-5x-10. Has she expanded it correctly? Please identify the mistakes and write the correct wa
Nimfa-mama [501]

The given expression is :

2xx+3-5(x-2)

We know that, x{\cdot}x=x^2

=2x^2+3-5(x-2)\\\\=2x^2+3+(-5)(x)+(-5)(-2)\\\\=2x^2+3-5x+10

Aleena expands 2xx+3-5(x-2) as 2x²+3-5x-10. She is mistaken because the sign before 10 should be +10 instead of -10. Hence, the correct expanded form is 2x²+3-5x+10. Hence, this is the required solution.

5 0
3 years ago
Helpppppppppppppppppppp
Nonamiya [84]

Answer:

a. 3

b. 6

and i got the last answer as 11

I am not too sure about the last one, sorry. Hope this helped!

Step-by-step explanation:

5 0
3 years ago
1) solve for w: 3w - 10 = 4w + 5<br> 2) solve for t:6 -2t &gt;18
Gre4nikov [31]
Problem # 1
 3w-10=4w+5
(3w-10) + (10-4w) = (4w+5) + (10-4w)
(3w-10) + (-4w+10) = (4w+5) + (-4w +10)
3w-10-4w+10 = 4w +5 -4w +10
3w-4w=15
-w=15
w= -15 (w is negative 15)

problem #2.
6-2t > 18
6-2t-6 > 18-6
-2t > 12 
(-1) (-2t) >  12 (-1)
2t > -12
next divide by 2
2t/2 > -12/2
 t >  -6     (t is greater then negative 6)

 
5 0
3 years ago
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