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monitta
1 year ago
14

Question 2-20

Mathematics
1 answer:
xeze [42]1 year ago
3 0

Weight of one apple is 8 ounces.

We have to calculate the weight of one apple. For that firstly, we have to calculate the weight of one apple in pounds because we have been given the weight of 96 apples in pounds. After that, we will convert it into ounces and we know that one pound is equal to 16 ounces.

A bushel has 96 apples.

We have been given weight of 1 bushel which is 48 pounds.

Weight of 96 apples = 48 pounds

We have to calculate weight of one apple.

Weight of one apple = 48/96 = 1/2 pound

1 pound = 16 ounces.

Now, we have to convert pounds into ounces

Weight of one apple = 1/2 * 16 ounces

= 8 ounces

Hence, the answer is 8 ounces.

To find more about how to calculate weight.

brainly.com/question/23245710

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Using inductive reasoning, the best answer from the given shapes is:
B) In a parallelogram, consecutive angles are supplementary.
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Jack sold 30 glasses of lemonade in 5 hours.Which of the following should be used to find the rate per hour of jacks lemonade se
avanturin [10]

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D

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4 0
2 years ago
Can you explain it and help me out please​
Anarel [89]

Answer:

c.

Step-by-step explanation:

2x² - 4x - 3 = 0

x= \frac{-b+/-\sqrt{b^{2}-4ac} }{2a} \\\\x= \frac{-(-4)+/-\sqrt{(-4)^{2}-4*2*(-3)} }{2*2} \\\\x= \frac{4+/-\sqrt{16+24} }{4} \\\\x= \frac{4+/-\sqrt{40} }{4} = \frac{4+/-2\sqrt{10} }{4}=\frac{2+/-\sqrt{10} }{2}

6 0
3 years ago
Read 2 more answers
Rita is thinking of two numbers. Adding 4 times the first number and 9 times the second number gives a total of 1. Also, adding
charle [14.2K]

Answer:

first number is negative 2, second is 1

Step-by-step explanation:

-2×4= -8 1×9=9

-8+9=1

-2×4= -8 1×6=6

-8+6= -2

hope this helped

6 0
3 years ago
Use mathematical induction to show that 4^n ≡ 3n+1 (mod 9) for all n equal to or greater than 0
cestrela7 [59]
When n=0, you have

4^0=1\equiv3(0)+1=1\mod9

Now assume this is true for n=k, i.e.

4^k\equiv3k+1\mod9

and under this hypothesis show that it's also true for n=k+1. You have

4^k\equiv3k+1\mod9
4\equiv4\mod9
\implies 4\times4^k\equiv4(3k+1)\mod9
\implies 4^{k+1}\equiv12k+4\mod9

In other words, there exists M such that

4^{k+1}=9M+12k+4

Rewriting, you have

4^{k+1}=9M+9k+3k+4
4^{k+1}=9(M+k)+3k+3+1
4^{k+1}=9(M+k)+3(k+1)+1

and this is equivalent to 3(k+1)+1 modulo 9, as desired.

3 0
3 years ago
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