Answer:
3 years
Step-by-step explanation:
set two equations in inches and equate
Zeroes of a function are the values of x when f(x) = 0
So to find the zeroes of the function from the graph search for the points whose y-coordinates = 0
The y-coordinates of the point = 0, if the points lie on the x-axis
That means the zeroes of the function are the points of intersection between the graph and the x-axis
let us see that in the graph
I will draw it and post it here
From the graph
The graph intersects x-axis at points (-7, 0) and (-2, 0)
Then the zeroes of the function are (-7, 0) and (-2, 0)
Let us make the table
x f(x)
-2 0
-1 6
0 14
1 24
2 36
Answer: If a number is rational, it can be represented as a simple fraction, it can be written as a terminating decimal, and a repeating decimal.
If a number is irrational, it cannot be represented as a simple fraction, it cannot be written as a terminating decimal, and not as a repeating decimal. It never ends, never repeats, just like the constant pi.
Step-by-step explanation:
So if a number is rational, it can be represented as a simple fraction, it can be written as a terminating decimal, and a repeating decimal.
If a number is irrational, it cannot be represented as a simple fraction, it cannot be written as a terminating decimal, and not as a repeating decimal. It never ends, never repeats, just like the constant pi.
Answer:
b. slope: -5; y-intercept: 7
Step-by-step explanation:
We are given the equation:
y + 5x = 7
To find the slope and y-intercept of the line, it would be helpful to get the equation into slope-intercept form. The slope-intercept form of a line is:
y = mx + b
where m is the slope and b is the y-intercept.
Lets get the given equation into slope-intercept form.
y + 5x = 7
Subtract 5x from both sides.
y = -5x + 7
Now we have the equation in slope-intercept form. By looking at the equation, we can see that the slope is -5 and that the y-intercept is 7.
The correct answer choice would be b.
I hope you find my answer and explanation to be helpful. Happy studying.
