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Llana [10]
1 year ago
10

2x^{2} + 20x + 48Completely factor the given polynomial, if possible. If the polynomial cannot be factored write "not factorable

".
Mathematics
1 answer:
astra-53 [7]1 year ago
4 0

Given:

2x^2+20x+48

To find the factors:

The given equation can be written as,

\begin{gathered} 2x^2+20x+48=2x^2+8x+12x+48 \\ =2x(x+4)+12(x+4)_{} \\ =(x+4)(2x+12)_{} \\ =2(x+4)(x+6) \end{gathered}

Hence, the factors are 2,(x+4), and (x+6).

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Answer:7043.82

It would be 4200 x 1.09 which is the interest to the power of 6 for the number of years which would then give you 4200 x 1.09^6. This will then give the answer of 7043.82
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Vikentia [17]

Answer:

9.89 m

Step-by-step explanation:

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x is the opposite (O)

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sin=O/H

H=O/sin

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=9.89187169943418

3 SF

9.89 m

8 0
3 years ago
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Consider the statement that the product of two of the numbers 651000 − 82001 + 3177, 791212 − 92399 + 22001, and 244493 − 58192
GenaCL600 [577]

Answer:

a c

Step-by-step explanation:

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3 years ago
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Verizon [17]

If f(x) has an inverse on [a, b], then integrating by parts (take u = f(x) and dv = dx), we can show

\displaystyle \int_a^b f(x) \, dx = b f(b) - a f(a) - \int_{f(a)}^{f(b)} f^{-1}(x) \, dx

Let f(x) = \sqrt{1 + x^3}. Compute the inverse:

f\left(f^{-1}(x)\right) = \sqrt{1 + f^{-1}(x)^3} = x \implies f^{-1}(x) = \sqrt[3]{x^2-1}

and we immediately notice that f^{-1}(x+1)=\sqrt[3]{x^2+2x}.

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\displaystyle \int_0^2 f^{-1}(x+1) + f(x) \, dx

Splitting up terms and replacing x \to x-1 in the first integral, we get

\displaystyle \int_1^3 f^{-1}(x) \, dx + \int_0^2 f(x) \, dx = 2 f(2) - 0 f(0) = 2\times3+0\times1=\boxed{6}

7 0
1 year ago
Find each function value f(-4) if f(x) = -5x - 3
Firlakuza [10]

Answer: f(-4) = 17

Step-by-step explanation: Substitute (-4) for x.

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4 0
2 years ago
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