Answer:
The area of the piece of construction paper is ![\frac{261}{4} inches^2](https://tex.z-dn.net/?f=%5Cfrac%7B261%7D%7B4%7D%20inches%5E2)
Step-by-step explanation:
Length of construction paper =![6 \frac{3}{4} inches](https://tex.z-dn.net/?f=6%20%5Cfrac%7B3%7D%7B4%7D%20inches)
=![\frac{27}{4} inches](https://tex.z-dn.net/?f=%5Cfrac%7B27%7D%7B4%7D%20inches)
Width of construction paper = ![9 \frac{2}{3} inches](https://tex.z-dn.net/?f=9%20%5Cfrac%7B2%7D%7B3%7D%20inches)
= ![\frac{29}{3} inches](https://tex.z-dn.net/?f=%5Cfrac%7B29%7D%7B3%7D%20inches)
Area of construction paper =![Length \times Width](https://tex.z-dn.net/?f=Length%20%5Ctimes%20Width)
Area of construction paper = ![\frac{27}{4} \times \frac{29}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B27%7D%7B4%7D%20%20%5Ctimes%20%5Cfrac%7B29%7D%7B3%7D)
= ![\frac{261}{4} inches^2](https://tex.z-dn.net/?f=%5Cfrac%7B261%7D%7B4%7D%20inches%5E2)
Hence the area of the piece of construction paper is ![\frac{261}{4} inches^2](https://tex.z-dn.net/?f=%5Cfrac%7B261%7D%7B4%7D%20inches%5E2)
Why did you delete my answer
Answer: Heyaa! :)
<em>Slope: </em>−1
<em>y-intercept: </em>(0,−3)
<em>Slope:</em> 4
<em>y-intercept: </em>(0,−5)
<em>Slope:</em> 2
<em>y-intercept:</em> (0,2)
Slope: −1
<em>y-intercept:</em> (0,4)
- <em>5. 3x+4y=-12 = - 3/4</em>
<em>Slope: </em>−3/4
<em>y-intercept: </em>
(0,−3)
Hopefully this helps<em> you!</em>
<em />
- Matthew
The question seems incomplete ; as the total number of tickets to be sold isn't given.
Answer:
61 / X
Step-by-step explanation:
Let's take the total Number of tickets to be sold as : X
Number of tickets sold on Thursday = 47
Number sold on Friday = 14
Fraction of tickets available for sale on Saturday :
(Total number of tickets already sold) / Total number of tickets to be sold
(Thursday + Friday sales) / total number of tickets to be sold
Fraction available for sale on Saturday = (47+14) / X
Fraction available for sale on Saturday = 61 / X
Kindly put value of x = total number of tickets available for sale to get the exact fraction.