In outer space, a constant force is applied to a 33.2 kg probe initially at rest. The probe moves a distance of 101 m in 15 s. W
1 answer:
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⁻Answer:
Ne=1.8 *10^37
Explanation:
Current density J=Iₐ /(πr²)
= 8/(π* (1.5*10⁻³/2)²)= 4.53*10⁶ A/m²
Drift velocity = J/ne =4.53*10⁶ /(8.5×1028 *1.6×10−19 ) = 3.33 ×10−4 m/s
volume = πr²h= π * (1.5*10⁻³/2)² * 3 = 5.3 ×10−6 m³
Ne=1.8 *10^37
Answer:
The magnitude of the vector addition is approximately 10.38
Explanation:
Recall that the vectors add easily in component form, just by adding component by component:
A = (6.7, -2.3)
B = (-5.5, 4.5)
C = (3.2, 7.2)
A + B + C = (6.7- 5.5 + 3.2, -2.3 + 4.5 + 7.2 ) = (4.4, 9.4)
Then, this vector's magnitude is calculated via: