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JulijaS [17]
3 years ago
7

CORRECT ANSWER WILL BE REWARDED BRAINLIEST

Physics
1 answer:
Mandarinka [93]3 years ago
7 0

Answer:

What is 2^-3 x 3^-2 as a fraction?

What is (-2)^-3 x (-3)^-2 as a fraction

Explanation:

I need these pls. SORRYYY

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A bowl-shaped depression formed by a mountain glacier is termed a(n) ____________.
Andrej [43]
A bowl-shaped depression formed by a mountain glacier is termed a cirque.
3 0
4 years ago
Help me pls its for my science class i need to show my work
Lostsunrise [7]

Answer:

P = 5880  J

Explanation:

Given that,

The mass of the block, m = 30 kg

The block is sitting at a height of 20 m.

The block will have gravitational potential energy. The formula for gravitational potential energy is given by :

P=mgh\\\\=30\times 9.8\times 20\\\\=5880\ J

So, the required potential energy is equal to 5880  J.

6 0
3 years ago
If the action force is the swimmer pushing water in the leftward direction, what is the reaction force?
Sphinxa [80]
  • According to Newton's Third Law of Motion, to every action, there is an equal and opposite reaction; action and reaction act on different bodies.
  • Here, the action force is in the leftward direction, so the reaction will be in the opposite direction.
  • If the action force is the swimmer pushing water in the leftward direction, then the reaction force is in the rightward direction.
  • And the reaction force will be given by the water on the swimmer.

<u>Answer</u><u>:</u>

<u>The </u><u>reaction </u><u>force </u><u>is </u><u>the </u><u>water </u><u>pushing </u><u>the </u><u>swimmer </u><u>in </u><u>the </u><u>rightward </u><u>direction</u><u>.</u>

Hope you could get an idea from here.

Doubt clarification - use comment section.

3 0
2 years ago
A crate of books is to be put on a truck with the help of some planks sloping up at 36◦ . The mass of the crate is 80 kg, and th
Dafna11 [192]

Answer:

F= 2.86KN

Explanation:

The attached diagram shows the motion of crate on a single line The forces acting on it have been resolved as shown in the attached figure.The kinetic friction opposes the motion.Now crate is moving with constant speed so the acceleration is constant.

Applying Newton's second law to determine the force F and also substituting the values for F_{k} to eliminate normal force

$\sum_F = ma

Now a_{x}  and  a_{y} components are zero

Horizontal and vertical forces are Force on crate, weight of crate and kinetic friction

$\sum F_{x} = Fcos\theta-f_{k}-mgsin\theta=0

$\sum F_{y} = F_{n}- Fsin\theta-mgcos\theta=0

therefore f_{k} = \mu_{k} F_{n}

Fcos\theta- \mu_{k} F_{n}-mgsin\theta=0  >>>  (1)

F_{n}=Fsin\theta+mgcos\theta

By putting the above equation in equation 1 we get F

F=\frac{mg(sin\theta+\mu_{k}cos\theta) }{cos\theta-\mu_{k}sin\theta }

By putting values we get

F = \frac{(80kg)(9.81\frac{m}{s^{2} })(sin36+(0.8)cos36) }{cos36-(0.8)sin36}

F= 2860.8 N

F= 2.86KN

4 0
4 years ago
A child pulls a sled up a snow covered hill. The child does 405 J of work on the sled. If the child walks 15m up the hill, how l
solong [7]
15 x 405 = 6075N of force
6 0
3 years ago
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