Answer: Peak wavelength
{lambda max}
= 9.7*EXP{-7}meter
Which is approximately,
1 micro-meter.
Explanation: lambda{max} which is peak wavelength is inversely proportional to temperature {T}.This is given by the wiens displacement law.
Lambda max
=max displacement{Xmax} / T
For the first case at T = 6000K
Lambda max = 483 nano-meter
=483*EXP{-9}meter.
So let's solve for max displacement {Xmax}.
Xmax = T*lambda max
= 6000*483*EXP{-9}
=2.898*EXP{-3}kelvin-meter
Xmax would be constant during Temperature change.
Therefore lambda max at 3000K would be,
Lambda max
= {2.898*EXP{-3} K-m} / 3000K
= 9.7*EXP{-7} meter
Which is approximately,
1*EXP{-6} meter= 1 micro-meter
NOTE: EXP used here means 10^.
Answer:
Plasma is by far the most common form of matter. Plasma in the stars and in the tenuous space between them makes up over 99% of the visible universe and perhaps most of that which is not visible. On earth we live upon an island of "ordinary" matter.
Answer: The drag force goes up by a factor of 4
Explanation:
The <u>Drag Force</u> equation is:
(1)
Where:
is the Drag Force
is the Drag coefficient, which depends on the material
is the density of the fluid where the bicycle is moving (<u>air in this case)
</u>
is the transversal area of the body or object
the bicycle's velocity
Now, if we assume , and do not change, we can rewrite (1) as:
(2)
Where groups all these coefficients.
So, if we have a new velocity , which is the double of the former velocity:
(3)
Equation (2) is written as:
(4)
Comparing (2) and (4) we can conclude<u> the Drag force is four times greater when the speed is doubled.</u>
Answer:
Number 6:
• From the formula of force:
• But we need to get the acceleration, from the first newtons equation of motion
• v is the final velocity, but v is zero because the bullet came to rest.
• u is the initial velocity, u = 350 m/s
• a is the acceleration that we need
• t is the time, t = 0.0018 seconds.
» let's now substitute:
[ negative shows retârdation or deceleration or decrease in speed ]
• Therefore, let's find the force:
mass = 6g = (6/1000) kg = 0.006 kg
Answer:
a) 5m/s2
b) 4 sec
c) 6 sec
d) 90 m
e) Answer in the file attached as it is a graph
Explanation:
This question can be solved using equations of motion. The two equations are:
2(a)(s) = v² – u²
v = u + (a)(t)
a = acceleration
s = distance
v = final velocity
u = initial velocity
t = time
a) Given final velocity = 50m/s and initial velocity = 30 m/s for 160m journey
Using 2(a)(s) = v² - u²
2(a)(160) = 50² – 30²
320 (a) = 2500 - 900
a = 1600/320
a = 5m/s²
b) The acceleration remains constant throughout so we can use it in this part as well.
Using v = u + (a)(t)
50 = 30 + (5)(t)
t = 4 sec
c) The acceleration remains constant throughout so we can use it in this part as well. Now the initial velocity will be 0m/s and final will be 30m/s
Using v = u + (a)(t)
30 = 0 + 5(t)
t = 6 sec
d) The acceleration remains constant throughout so we can use it in this part as well. Now the initial velocity will be 0m/s and final will be 30m/s
Using 2(a)(s) = v² - u²
2(5) (s) = 30² – 0²
10(s) = 900
s = 90 m
e) Graphs are attached as image