Question

Draw an alkyl bromide with proper stereochemistry that can be used to synthesize the given alkene as the exclusive product via an E2 reaction. All chiral centers must have four bonds drawn. Does the alkyl bromide drawn give the provided alkene product via an E2 mechanism? Did you take stereochemistry and regiochemistry into account? Does every chiral center have all four bonds drawn

Answer 1

There is a cyclohexane with four methyl groups. Two of them are angled in the direction of the molecule with the darker bond. As a result, one of the bonds in the alkyl bromide's structure should contain bromine.

And this bromine should be facing the other way from the methyl groups, who should be facing toward for an E2 reaction to occur. This is so that an E2 reaction can take place when there is less steric interference in the molecule. An E2 reaction will require a lot more work to complete if the bromine is facing in the same direction as the methyl group. I will instead advocate for an E1 or a replacement product.

A cycloalkane, cyclohexane has the chemical formula C6H12. It is non-polar, cyclohexane. Colorless and combustible, cyclohexane has a characteristic detergent-like stench.

Learn more about cyclohexane here

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