Answer: I'm going to guess and say it is h2 or o2 I am not sure.
Explanation:
Answer:
k ≈ 9,56x10³ s⁻¹
Explanation:
It is possible to solve this question using Arrhenius formula:
![ln\frac{k2}{k1} = \frac{-Ea}{R} (\frac{1}{T2} -\frac{1}{T1} )](https://tex.z-dn.net/?f=ln%5Cfrac%7Bk2%7D%7Bk1%7D%20%3D%20%5Cfrac%7B-Ea%7D%7BR%7D%20%28%5Cfrac%7B1%7D%7BT2%7D%20-%5Cfrac%7B1%7D%7BT1%7D%20%29)
Where:
k1: 1,35x10² s⁻¹
T1: 25,0°C + 273,15 = 298,15K
Ea = 55,5 kJ/mol
R = 8,314472x10⁻³ kJ/molK
k2 : ???
T2: 95,0°C+ 273,15K = 368,15K
Solving:
![ln\frac{k2}{k1} = 4,257](https://tex.z-dn.net/?f=ln%5Cfrac%7Bk2%7D%7Bk1%7D%20%3D%204%2C257)
![\frac{k2}{k1} = 70,593](https://tex.z-dn.net/?f=%5Cfrac%7Bk2%7D%7Bk1%7D%20%3D%2070%2C593)
![{k2} = 9,53x10^3 s^{-1}](https://tex.z-dn.net/?f=%7Bk2%7D%20%3D%209%2C53x10%5E3%20s%5E%7B-1%7D)
<em>k ≈ 9,56x10³ s⁻¹</em>
I hope it helps!
Answer: left
Explanation: The element that appears farthest to the
✔ left
is written first in the chemical name of a covalent compound.