Pharmaceutical compounding (done in compounding pharmacies<span>) is the creation of a particular 1 History; 2 </span>Roles<span> These </span>ancient<span> compounders </span>produced<span> the first oils from plants and animals. The compounding </span>pharmacist<span> often extracted these crude </span>drugs<span> using water or alcohol to form extracts,</span>
Balanced equation:
Pb(SO₄)₂ + 2 Zn → 2 ZnSO₄ + Pb
From the equation we found that 2 moles of Zn form 2 moles of ZnSO₄
so 0.582 mole of Zn will produce 0.582 ZnSO₄
Molar mass of ZnSO₄ = 161.47 g/mole
Mass of ZnSO₄ formed = 161.47 x 0.582 = 94.0 grams
ANSWER:
2.65 g H2O
Explanation:
6.49g (co2) / 44.009g (co2) x 1 mol (co2) / 1 mol (h2o) x 1 mol (h2o)
=0.147 mol H2O
0.147 mol (H2O) / 1 mol (h2o) x 18.015 g (h2o)
=2.65 g H2O
39.25 g of water (H₂O)
Explanation:
We have the following chemical reaction:
2 H₂ + O₂ → 2 H₂O
Now we calculate the number of moles of each reactant:
number of moles = mass / molar weight
number of moles of H₂ = 14.8 / 2 = 7.4 moles
number of moles of O₂ = 34.8 / 32 = 1.09 moles
We see from the chemical reaction that 2 moles of H₂ will react with 1 mole of O₂ so 7.4 moles of H₂ will react with 3.7 moles of O₂ but we only have 1.09 moles of O₂ available. The O₂ will be the limiting reactant. Knowing this we devise the following reasoning:
if 1 moles of O₂ produces 2 moles of H₂O
then 1.09 moles of O₂ produces X moles of H₂O
X = (1.09 × 2) / 1 = 2.18 moles of H₂O
mass = number of moles × molar weight
mass of H₂O = 2.18 × 18 = 39.25 g
Learn more about:
limiting reactant
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Answer:
1.42m/s
Explanation:
velocity=displacement/time
v=50/35=1.42m/s