The problem express that the fraction of time
worked by the three people need to be equivalent to one person working full
time. This means that the fraction need to add up to one. We know one person
works ½ time on the project and another works one third 1/3 time.
Given:
A = the amount of time that the third person needs
to work on the job to add up to one
1 = ½ +1/3 + A
1 – ½ - 1/3 = A
To subtract the fractions put them all over a
common denominator. Use 3 * 2 as the denominator.
1=6/6, ½ = 3/6, 1/3 = 2/6
A = 6/6 – 3/6 – 2/6
<span>A = 1/6 , The third person must work on the project</span>
Answer:
True
Step-by-step explanation:
We can sue the pythagorean theorem to verify. 15^2+36^2 should equal the longest side squared or 39^2. If we plug in the numbers, it checks out!
Answer:
The correct answer would be the second option
Step-by-step explanation:
Answer:
Tanks of 15.3081 gallons and larger are considered too large.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
How large does a tank have to be to be considered too large
largest 2%, so at least the 98th percentile.
The 98th percentile is X when Z = 0.98. So it is X when Z = 2.054.
Tanks of 15.3081 gallons and larger are considered too large.
lDK
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