Question

How would i solve this?

Answer 1

FIRST FIND THE EQUATION OF THE LINE

I WILL USE THE POINTS (-94,24) AND (-54,12)

TO FIND THE GRADIENT

$m = \frac{y2 - y1}{x2 - x1} \\ m = \frac{12 - 24}{ - 54 - ( - 94)} \\ m = \frac{ - 24}{ - 54 + 94} \\ m = \frac{ - 24}{40} \\ m = \frac{ - 3}{5}$

THE m ABOVE IS THE GRADIENT.

I WILL USE THE POINT (-74,18) TO GET THE VALUE OF C IN THE EQUATION Y=MX+C

$15 = \frac{ - 3}{5} ( - 74) + c \\ 15 = \frac{222}{5} + c \\ c = 15 - \frac{222}{5} \\ c = \frac{ - 147}{5}$

THEREFORE THE EQUATION NOW IS

$y = \frac{ - 3}{5} x - \frac{147}{5} \\FOR THE X-INTERCEPT Y=0 SINCE IN THR X-AXIS Y=0..PLUG IN 0 IN THE PLACE OF Y TO GET X-INTERCEPT. [tex] \frac{ - 3}{5} x - \frac{147}{5} = 0 \\ \frac{ - 3}{5} x = \frac{147}{5} \\ x = \frac{147}{5} \div \frac{ - 3}{5} \\ x = - 49$

(-49,0)