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Xelga [282]
3 years ago
7

What is the total depreciation (at 10% rate) on a blower purchased 3 years ago for $499?

Mathematics
1 answer:
GrogVix [38]3 years ago
6 0

\bf \qquad \textit{Amount for Exponential Decay} \\\\ A=P(1 - r)^t\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &499\\ r=rate\to 10\%\to \frac{10}{100}\dotfill &0.10\\ t=\textit{elapsed time}\dotfill &3\\ \end{cases} \\\\\\ A=499(1-0.10)^3\implies A=499(0.9)^3\implies A=363.771 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \stackrel{\textit{total depreciation 499 - 363.771}}{135.229}~\hfill

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Would x - 4 be -4x or just leave it as x <br><br> pls answer
lilavasa [31]

\huge\text{Hey there!}

\large\text{Question: Would x - 4 be -4x or just leave it as x?}\\\\\large\textsf{Equation: x - 4}\\\\\large\text{NOTHING happens to your equation because you do NOT have}\\\large\text{any like terms to determine the result of -4x or x}\\\\\\\\\\\\\\\huge\textbf{Therefore, your answer is: \boxed{\mathsf{x - 4}}}\huge\checkmark\\\large\textbf{Since,  you didn't have like terms in this equation}

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3 0
3 years ago
Guys please help with this question thanks
erastova [34]
= 16 + 49 - 3(11)  - 4(10)
= 16 + 49 - 33 - 40
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3 0
3 years ago
Or
Cloud [144]

The value of (fg)(x)= 3x³+ x²

<h3>What is function?</h3>

An expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable).

Given:

f(x) = -3x+1

g(x) = x^{2}

Now, (fg)(x)

=f(x) * g(x)

=  (-3x+1) * (x^{2})

=-3x³+ x²

Hence, (fg)(x)= 3x³+ x²

Learn more about this concept here:

brainly.com/question/15068845

#SPJ1

6 0
2 years ago
Plz help fast Jack, John, Lily, and Sara want to take a picture together. In how many ways can they are arranged?
jasenka [17]

Answer:

The best estimate would be around 10-16

Step-by-step explanation:

The think is that they can be in many orders and since there is four of them it would be more orders.

Hope this helps

6 0
3 years ago
At what point will 3y=4x-6 and 8x-6y=-30 intercept
tester [92]

Answer:

The lines don't intercept

Step-by-step explanation:

we have

3y=4x-6

isolate the variable y

Divide by 3 both sides

y=\frac{4}{3}x-\frac{6}{3}

simplify

y=\frac{4}{3}x-2 -----> equation A

8x-6y=-30

Isolate the variable y

6y=8x+30

Divide by 6 both sides

y=\frac{8}{6}x-\frac{30}{6}

simplify

y=\frac{4}{3}x-5 -----> equation B

Compare equation A and equation B

The slopes are the same and the y-intercepts are different

Remember that

If two lines has the same slope, then the lines are parallel

therefore

In this problem line A and line B are parallel lines

The system of equations has no solution, because the lines don't intercept

3 0
3 years ago
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