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Effectus [21]
3 years ago
9

A=? B=? ({[correct answer marked BRAINLIEST]})

Mathematics
2 answers:
ANEK [815]3 years ago
7 0

Answer:

a) 2x + 18

b) 6x - 10

Step-by-step explanation:

a) 16x + 3 - 14x + 15

2x+ 18

b) 1/6 (24x - 60) + 2x

4x -10 + 2x

6x - 10

Alinara [238K]3 years ago
6 0

Step-by-step explanation:

a= 16x+3-14x+15

combine like terms, 16x-14x= 2x

so,

2x+3+15,

15+3=18

18=2x, divide 18 by 2

x=9

b)  *open the parenthesis* -1/6 *24x = -4x

-1/6*60 = -10

-4x- (-10)= -4x+10

-4x+10+2x= -4x+2x= -2x

-2x=10 = 2x=-10 = x=-5

Cheers!

You might be interested in
Solve 1/5x+3=10. Show all work and check it
iren2701 [21]
1/5x + 3 = 10

Subtract by 3 on both sides. 

1/5x = 7.

Now to isolate the variable, flip the coefficient in front of the variable and multiply both sides by it. 

5(1/5x) = 7(5)

x = 7(5)
x = 35

Now to check:

1/5(35) + 3 = 10

35/5 + 3 = 10

35/5 is 7.

7 + 3 = 10

10 = 10
5 0
3 years ago
Read 2 more answers
Lillian has $80 in a savings account. The interest rate is 10%, compounded annually.
arlik [135]
She will have 96.8 dollars in the saving account so she earned 16.8 dollars in interest
If this answered help you then please consider marking it as brainliest to help me level up to expert
5 0
3 years ago
I need help please as soon as possible with both :(
Over [174]

Answer:

X=0

(8,7)

Step-by-step explanation:

8 0
3 years ago
Please help FAST I need the answer along with you explaining the steps so I can get it thanks! I’ll give Brainlist also!
kupik [55]

Answer:

The equation of required line is: \mathbf{5x-8y+34=0}

Step-by-step explanation:

We need to write equation in the form Ax+By+C=0 of the line parallel to 5x-8y+12=0 and through the point (-2,3)

First we need to find slope and y-intercept of the required line.

Using equation of line  5x-8y+12=0 to find slope.

Since the given line and required lines are parallel there slope is same.

Writing equation in slope intercept form: y=mx+b where m is slope.

5x-8y+12=0 \\-8y=-5x-12\\\frac{-8y}{-8y}=\frac{-5x}{-8}-\frac{12}{-8}\\y=\frac{5}{8}x+\frac{3}{4}

So, the slope m = 5/8

The slope of required line is m=\frac{5}{8}

Now finding y-intercept using slope m=\frac{5}{8} and point(-2,3)

y=mx+b\\3=\frac{5}{8}(-2)+b\\3=\frac{-5}{4}+b\\b=3+\frac{5}{4}\\b=\frac{3*4+5}{4}\\b=\frac{12+5}{4}\\b=\frac{17}{4}

So, the equation of required line having slope m=\frac{5}{8}  and y-intercept b=\frac{17}{4}

y=mx+b\\y=\frac{5}{8}x+\frac{17}{4}\\y=\frac{5x+17*2}{8}\\y= \frac{5x+34}{8}  \\8y=5x+34\\5x-8y+34=0

So, The equation of required line is: \mathbf{5x-8y+34=0}

3 0
2 years ago
What is the perimiter of ABC with vertices A (-2,9), B(7-3), and c(-2,-3) in the coordinate plane?
Serggg [28]

Answer:

|AB| = √((7 - (-2))^2 + (-3 - 9)^2) = 15

|BC| = √((-2 - 7)^2 + (-3 - (-3))^2) = 9

|AC| = √((-2 - (-2))^2 + (-3 - 9)^2) = 12

Perimeter = 15 + 9 + 12 = 36

6 0
3 years ago
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