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AlekseyPX
3 years ago
8

Candice is making some party bags for her birthday party she has 96 stickers and 80 boxes of cookies she wants each party bags t

o be the same and she wants to use all of the stickers and cookie find the GCF of 96 and 80 to figure out how many party bags she can make
Mathematics
1 answer:
Irina-Kira [14]3 years ago
4 0

the greatest common factor 80 and 96 is 16. And so 16 party bags she can make .

<u>Step-by-step explanation:</u>

Here we have , Candice is making some party bags for her birthday party she has 96 stickers and 80 boxes of cookies she wants each party bags to be the same and she wants to use all of the stickers and cookie  . we need to find how many party bags she can make . Let's find out:

Let's calculate GCF of 96 & 80 as :

Prime factors of 96 are :

⇒ 2^5(3)^1

Prime factors of 80 are :

⇒ 2^4(5)^1

Therefore , GCF is common factor of Prime factors of 96 and Prime factors of 80 i.e. 2^4 = 16 .

We found the factors and prime factorization of 80 and 96. The biggest common factor number is the GCF number.  So the greatest common factor 80 and 96 is 16.

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Yes.

Step-by-step explanation:

According to medical science, a body temperature considered normal (that is, below fever) in degrees Fahrenheit is 98ºF, while its equivalent in degrees Celsius is 36.6ºC. Therefore, a body temperature of 39ºC is higher than 98ºF, being equivalent to 102.2ºF.

This is verified by applying the conversion formula from Celcius to Fahrenheit:

(39 x 9/5) + 32 = X

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2 years ago
The graph of F(x) can be stretched vertically and flipped over the x-axis to produce the graph of G(x). If F(x) = x^2, which of
katrin [286]

The transformed function is G(x) = -4x² after applying the transformation stretched vertically and flipped over the x-axis option (C) G(x) = -4x² is correct.

<h3>What is a function?</h3>

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

The options are missing.

The options are:

A. G(x) = 4x²

B. G(x) = -(1/4)x²

C. G(x) = -4x²

D. G(x) = (1/4)x²

We have an equation of a function F(x)  

F(x) = x²

The transformation F(x) can be stretched vertically and flipped over the x-axis to produce the graph of G(x)

To stretch vertically if the function is multiplied by a constant value

f(x) = ax²

To flip over the x-axis if multiply by negative value.

g(x) = -ax²

From the options

G(x) = -4x²

Thus, the transformed function is G(x) = -4x² after applying the transformation stretched vertically and flipped over the x-axis option (C) G(x) = -4x² is correct.

Learn more about the function here:

brainly.com/question/5245372

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2 years ago
Alex, Toby and Samuel are playing a game together.
Shalnov [3]

Answer:

1/9

Step-by-step explanation:

There are three places and three people.

Times them together for the total outcomes:

1/3 x 1/3= 1/9

8 0
3 years ago
I have 100 items of product in stock. The probability mass function for the product's demand D is P(D=90)=P(D=100)=P(D=110)=1/3.
masya89 [10]

Answer:

The probability mass function for the items sold is

P_X(k) = \left \{ {\frac{1}{3} \, \, \, {k=90} \atop \, \frac{2}{3} \, \, \, {k=100}} \right.

The mean is 96.667

The variance is 22.222

b) The probability mass function for the unfilled demand due to lack of stock is

P_Y(k) = \left \{ {\frac{2}{3} \, \, \, {k=0} \atop \, \frac{1}{3} \, \, \, {k=10}} \right.

The mean is 3.333

The variance is 33.333

Step-by-step explanation:

If the demand is higher than 100, then you will sell 100 items only. Thus, there is a probability of 1/3+1/3 = 2/3 that you will sell 100 items, while there is a probability of 1/3 that you will sell 90.

The probability mass function for the items sold is

P_X(k) = \left \{ {\frac{1}{3} \, \, \, {k=90} \atop \, \frac{2}{3} \, \, \, {k=100}} \right.

The mean is 1/3 * 90 + 2/3 * 100 = 290/3 = 96.667

The variance is V(X) = E(X²)-E(X)² = (1/3*90² + 2/3*100²) - (290/3)² = 200/9 = 22.222

b) If order to be unfilled demand, you need to have a demand of 110, which happens with probability 1/3. In that case, the value of the variable, lets call it Y, that counts the amount of unfilled demand due to lack of stock is 110-100 = 10. In any other case, the value of Y is 0, which would happen with probability 1-1/3 = 2/3. Thus

P_Y(k) = \left \{ {\frac{2}{3} \, \, \, {k=0} \atop \, \frac{1}{3} \, \, \, {k=10}} \right.

The mean is 2/3 * 0 + 1/3 * 10 = 10/3 = 3.333

The variance is 2/3*0² + 1/3*10² = 100/3 = 33.333

4 0
3 years ago
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