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Anika [276]
3 years ago
6

A dc shunt generator rated at 85 kW produces a voltage of 280 V. The brush voltage drop is 2.5 V, and the armature and field res

istances are 0.09 Ω and 115 Ω, respectively. The generator delivers rated current at rated speed and rated voltage. (a) Calculate the field, armature, and load currents versus load. Test the equations with the rated load. (b) Determine the terminal voltage at no-load and at rated load conditions. (c) Calculate the voltage regulation of the generator. Use the no-load voltage as the base value. (d) Plot the terminal voltage as a function of the load. Determine the load that corresponds to a 5% voltage drop using the no-load voltage as the base

Engineering
1 answer:
dalvyx [7]3 years ago
3 0

Answer:

(a) Calculate the field, armature, and load currents versus load = 306A

(b) Determine the terminal voltage at no-load and at rated load conditions = 300V

(c) Calculate the voltage regulation of the generator. Use the no-load voltage as the base value = 6.67%

(d) Plot the terminal voltage as a function of the load. Determine the load that corresponds to a 5% voltage drop using the no-load voltage as the base = 294.74V

Explanation:

CHECK THE ATTACHED FILES FOR DETAILED EXPLANATION.

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